The first false statement in the proof as it stands is in Line 5, where it is claimed that a line of length 2.83 is congruent to a line of length 4.47. This mistake cannot be corrected by adding lines to the proof.
_____
The first erroneous tactical move is in Line 4, where the length of DE is computed, rather than the length of FD. This mistake can be corrected by adding lines to the proof.
A correct SAS proof would use segment FD in Line 4, so it could be argued that the first mistake is there.
Answer:
it can literally be anything you didnt give any information about the first number
Step-by-step explanation:
Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
Answer:
The resulting graph is 
.
Step-by-step explanation:
The resulting function is of the form:
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
- Amplitude, dimensionless.
- Midpoint value, dimensionless.
The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: 
. According to the graph, the function is bounded between 5 (
) and -5 (
), and the midpoint value () is 0. The amplitude is determined by the following calculation:
If 
and 
, then:
The resulting graph is .
