Hi,
The two numbers should be 12 and 30. 12=2x2x3 while 30=2x3x5.
Their HCF is 2x3=6 and their LCM is 2x3x2x5. Because of their HFC, we know that they are both multiple of 6. Also, the question says they both are GREATER than 6, so they can’t be 6 but are 6 times “something”. Thanks to the LCM, we know that “something” is equal to 2 for the first number and to 5 for the second one, the numbers hence being 12 and 30.
I hope this helps. If I was not clear enough or if you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.
Step-by-step explanation:
One side of a triangle is 9 cm and other side is 37 cm. We need to find what could be the length of the third side of the triangle.
If we add one and other side i.e. 9 cm + 37 cm = 46 cm
If we subtract one and other side i.e. 37 cm - 9 cm = 28 cm
We know that, the length of the third side must be less than the sum of the other two sides and greater than the difference between the other two sides.
Thus, the third side could be between 46 cm and 28 cm.
Step-by-step explanation:
Individual differences is the answer hshahaha
Answer:
log(4x3y)
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Put brackets around the first two tems.
y = (x^2 - 8x) + 29
Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.
1/2 (- 8) = - 4
(- 4)^2 = 16
y = (x^2 - 8x + 16) + 29
Subtract 16 outside the brackets.
y = (x^2 - 8x + 16) + 29 - 16
Do the subtraction
y = (x^2 - 8x + 16) + 13
Represent what is inside the brackets as a square.
y = ( x - 4)^2 + 13
The answer is A
