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frez [133]
4 years ago
10

SORRY ABOUT THE LAST ONE HELP ME PLES ASWDFEGHRJKT

Mathematics
2 answers:
iVinArrow [24]4 years ago
7 0

Answer:

6A: 3.5 6B: -2.5+3.5=1    4: yes,no,no,yes

Step-by-step explanation:

I dont know the rest but here

bija089 [108]4 years ago
5 0

Answer:

6. -2.5 + 3 = 0.5

Part B. -2.5 + x = y

4. a. Yes

   b. No

   c. No

   d. Yes

1. C. -1/8 points

3. a. -3.7 + 8 = positive number                  8 = a.           4/3 = d.                                                            

   b. -8 - 1/1/3 = negative number              -8 = b, c.         -5 = b, d.                                                                            

   c. -8 + 8 = 0                                          -4.9 = b, d.     -5.4 = b, d.                                                                                                            

   d. -4.52 + -4.9 = negative number       3.8 = a, d.    3.86 = a, d.                                                                                                

Step-by-step explanation:

Those are the correct answers.

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Write the following ratio in the simplest form<br><br>1/2:3/5
Alla [95]

Answer:

Step-by-step explanation:

\frac{1}{2}:\frac{3}{5}=\frac{1*5}{2*5}:\frac{3*2}{5*2}\\\\=\frac{5}{10}:\frac{6}{10}\\\\= 5:6

5 0
3 years ago
Plz help and Thank you :/
marin [14]

Answer:

ok that is correct because you start with 25 and then add 9 each week so 25+9w

Step-by-step explanation:

8 0
3 years ago
(Does this represent a linear function)<br> (3,6)(0,2)(3,5)
Lina20 [59]
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3 0
3 years ago
A rectangle has width w inches and height h inches, where the width is twice the height. Both w and h are functions of time t, m
vichka [17]

Answer:

D.

Step-by-step explanation:

Area=w*h

w*h=(2h)*(h)=2h^2

dA/dt=2(2h)=4h

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6 0
4 years ago
Given that ABCD~JKLM <br> find the ratio of the perimeter of ABCD to JKLM
Westkost [7]

Answer:

The ratio of the perimeter of ABCD to JKLM is;

b. 3/5

Step-by-step explanation:

Given that ABCD ~ JKLM, where;

DC and ML are corresponding sides

AD and JM are corresponding sides

AB and JK are corresponding sides

Therefore;

DC/ML = AD/JM = AB/JK

Plugging in the values of the variables gives;

9/15 = z/10 = x/12

∴ z = 10×9/15 = 6

x = 12×9/15 = 7.2

9/15 = 6/y

y = 6 ×15/9 = 10

The perimeter of the quadrilateral ABCD = AB + BC + DC + AD

∴ The perimeter of the quadrilateral ABCD = 6 + 6 + 9 + 7.2 = 28.2

The perimeter of the quadrilateral JKLM = JK + JM + ML + LK

∴ The perimeter of the quadrilateral JKLM = 12 + 10 + 15 + 10 = 47

The ratio of the perimeter of ABCD to JKLM = 28.2/47 =0.6 = 3/5.

4 0
3 years ago
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