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zubka84 [21]
3 years ago
7

Which measurement is not equivalent to the others?

Mathematics
1 answer:
Scrat [10]3 years ago
7 0
If you would like to know which measurement is not equivalent to the others, you can calculate this using the following steps:

1 quart = 4 cups = 2 pints = 32 fl. oz.

2 quarts = 2 * 4 cups = 8 cups
2 quarts = 2 * 2 pints = 4 pints
2 quarts = 2 * 32 fl. oz. = 64 fl. oz.

Not equivalent: <span>72 fl. oz.</span>
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It's a flat horizontal line so the slope is 0

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Answer:

20. AB = 42

21. BC = 28

22. AC = 70

23. BC = 20.4

24. FH = 48

25. DE = 10, EF = 10, DF = 20

Step-by-step explanation:

✍️Given:

AB = 2x + 7

BC = 28

AC = 4x,

20. Assuming B is between A and C, thus:

AB + BC = AC (Segment Addition Postulate)

2x + 7 + 28 = 4x (substitution)

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2x + 35 = 4x

35 = 4x - 2x

35 = 2x

Divide both side by 2

17.5 = x

AB = 2x + 7

Plug in the value of x

AB = 2(17.5) + 7 = 42

21. BC = 28 (given)

22. AC = 4x

Plug in the value of x

AC = 4(17.5) = 70

✍️Given:

AC = 35 and AB = 14.6.

Assuming B is between A and C, thus:

23. AB + BC = AC (Segment Addition Postulate)

14.6 + BC = 35 (Substitution)

Subtract 14.6 from each side

BC = 35 - 14.6

BC = 20.4

24. FH = 7x + 6

FG = 4x

GH = 24

FG + GH = FH (Segment Addition Postulate)

4x + 24 = 7x + 6 (substitution)

Collect like terms

4x - 7x = -24 + 6

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Divide both sides by -3

x = 6

FH = 7x + 6

Plug in the value of x

FH = 7(6) + 6 = 48

25. DE = 5x, EF = 3x + 4

Given that E bisects DF, therefore,

DE = EF

5x = 3x + 4 (substitution)

Subtract 3x from each side

5x - 3x = 4

2x = 4

Divide both sides by 2

x = 2

DE = 5x

Plug in the value of x

DE = 5(2) = 10

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Plug in the value of x

EF = 3(2) + 4 = 10

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DE = 10 + 10 (substitution)

DE = 20

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The sum of two integers is 33. The larger is 6 more than twice the smaller. Find the two
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Answer:

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Step-by-step explanation:

Hi there!

Let x be equal to the larger integer.

Let y be equal to the smaller integer.

<u>1) Construct equations</u>

  1. x+y=33 (The sum of two integers is 33)
  2. x=6+2y (The larger is 6 more than twice the smaller)

<u>2) Solve for one of the integer</u>

Isolate x in the first equation

x+y=33\\x=33-y

Plug the first equation into the second

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<u />

<u>3) Solve for the other integer</u>

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Plug in y (9)

x+9=33\\x=33-9\\x=24

Therefore, the larger integer is 24.

I hope this helps!

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