Download photo math for equations like this, it will also give you it step by step :)
Answer: the second option
explanation: below
First, divide the shape into two figures ( a semicircle and a rectangle)
Then, find the are or the two shapes using the area formula for a semicircle (

) and the are formula for a rectangle (base x height)
Finally, add the two areas together and you have your answer
Answer:
Yes, it is true that
is a factor of
.
Step-by-step explanation:
Let us try to factorize 

Let us try to make a whole square of the given terms:

--------------
Formula used above:

In the above equation, we had
.
--------------
Further solving the above equation, taking
common out of 

Taking
common out of the above term:

So, the two factors are
.
The statement that
is a factor of
is <em>True.</em>