Q4. Find the range, standard deviation, and variance for the following sample data:

Mathematics

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

40 I think but no I think

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In the parallelogram below, solve for X Options 4 10 25 100

Sever21 [200]

Answer:

Step-by-step explanation:

The sides of a parallelogram are parallel, which means 25x and 100 are alternate angles and therefore equal.

25x=100

x=4

7 0

2 years ago

The total rainfall in forks , washington, october was 8 3/8 in. in september ,60% less rainfall fell in October

iren2701 [21]

Rainfall in October in Forks, Washington = 8 3/8 inches
= 67/8 inches
Percentage of rainfall that has fallen less in September in Forks, Washington = 60%
Let us assume the amount of rainfall in September in Forks, Washington = x
Then
100x/60 = 67/8
10x/6 = 67/8
5x/3 = 67/8
5x * 8 = 67 * 3
40x = 201
x = 201/40
= 5 1/40 inches
So the amount of rainfall in September in Washinton is 5 1/40 inches.

6 0

3 years ago

Angle 1 and Angle 2 form a linear pair. If m41 = (5x + 9)® and m22 = (3x + 11)", find the measure of

MissTica

Answer:

2/23/140+50ismmm/50

148/'320"120+4640=%40=40

7 0

3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

Solution:

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$