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2 years ago

Giving crown

Mathematics

1 answer:

kompoz [17]2 years ago

5 0

Answer:

3) = B

<h3>Explanation:</h3>

There are 147 trees.

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Which sets of ordered pairs represent functions from A to B? (Select all that apply.) A = {a, b, c} and B = {3, 4, 5, 6}

sesenic [268]

Answer:

See Explanation

Step-by-step explanation:

The question has mission options; However, the question is still solvable.

Given

$A = \{a,b,c\}$

$B = \{3,4,5,6\}$

Required

Determine possible ordered pairs of A to B

A function is of the form (x,y)

Let A be the range of the function and B, the domain

Let (x,y) be a function of A to B, where x represents any of the values in A sets and y represents any of the values in B

A ordered pair can only be regarded as a function if and only if it has unique y-values

Hence, a possible ordered pair is:

$(A,B) = \{(a,3),(b,4),(c,5)\}$

Another possible ordered pair is

$(A,B) = \{(a,4),(b,5),(c,6)\}$

Note that there as as many as possible ordered pair as long as the y-values are unique

5 0

3 years ago

If a translation maps point (3, 2) to (5,3); or T:(3, 2) - (5,3), indicate the image for (2,4)

Zinaida [17]

Answer:

Step-by-step explanation:

Note that for (3, 2) → (5, 3)

The x- coordinate of the image is 2 more (+ 2) than the original and the y- coordinate of the image is 1 more (+ 1) than the original, that is

(x, y ) → (x + 2, y + 1 ) ← rule to obtain image, hence

(2, 4 ) → (2 + 2, 4 + 1 ) → (4, 5 ) → A

6 0

2 years ago

What set of reflections would carry hexagon ABCDEF onto itself?

Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself

First; we test the given options, until we get the true option

(a) y=x, x-axis, y=x, y-axis

The rule of reflection y =x is:

$(x,y) \to (y,x)$

The rule of reflection across the x-axis is:

$(x,y) \to (x,-y)$

So, we have:

$(y,x) \to (y,-x)$

The rule of reflection y =x is:

$(x,y) \to (y,x)$

So, we have:

$(y,-x) \to (-x,y)$

Lastly, the reflection across the y-axis is:

$(x,y) \to (-x,y)$

So, we have:

$(-x,y) \to (x,y)$

So, the overall transformation is:

$(x,y) \to (x,y)$

Notice that, the original and final coordinates are the same.

This means that:

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself