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3 years ago

The terminal point determined is in what quadrant?

Mathematics

1 answer:

jeyben [28]3 years ago

5 0

Answer:

quadrant 4

Step-by-step explanation:

I find it helpful to remember that the cosine is positive in the right half-plane, and the sine is positive in the top half-plane. Knowing the relationship between sine and cosine and all the other trig functions, you can figure their signs in the various quadrants.

The bottom half-plane (sin < 0) and the right half-plane (cos > 0) overlap in the 4th quadrant.

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Da A Solve the equation 2x^2+3=0

Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra I

Solving quadratics

Algebra II

Imaginary root i

√-1 = i

Step-by-step explanation:

Step 1: Define

Identify

2x² + 3 = 0

Step 2: Solve for x

[Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
[Division Property of Equality] Divide 2 on both sides: x² = -3/2
[Equality Property] Square root both sides: x = ±√(-3/2)
Simplify: x = ±i(√6 / 2)

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3 years ago

One number is four less than a second number. Three times the first is 13 more than 4 times the

Gala2k [10]

Answer:

sup

Step-by-step explanation:

5 0

3 years ago

Solve: 3 = -2v - V V=

Y_Kistochka [10]

Answer:

V = −1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3=−2v−v

3=−2v+−v

3=(−2v+−v)(Combine Like Terms)

3=−3v

Step 2: Flip the equation.

−3v=3

Step 3: Divide both sides by -3.

−3v = 3

-3 -3

v=−1

4 0

4 years ago

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An artist is creating a large butterfly sculpture outside a museum. There is a circular dot on each wing made out of a metal rin

IgorLugansk [536]

$\bf \textit{"The distance around each dot is 24}\pi \textit{ inches."}\\\\
\textit{circumference of a circle}\\\\
C=2\pi r\quad 
\begin{cases}
r=radius\\
-----\\
C=24\pi 
\end{cases}\implies 24\pi =2\pi r\implies \cfrac{24\pi }{2\pi }=r
\\\\\\
\boxed{12=r}\\\\
-------------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\quad 
\begin{cases}
r=radius\\
-----\\
r=12
\end{cases}\implies A=\pi 12^2\implies A=144\pi$

6 0

4 years ago

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Write each of the following expressions without using absolute value. |z−6|−|z−5|, if z<5

Andre45 [30]

Answer: 6 - 5

Step-by-step explanation:

|z - 6| - |z - 5| ; z < 5

Since z < 5, then

|z - 6| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:

-(z - 6) = -z + 6

|z - 5| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:

-(z - 5) = -z + 5

Now subtract them without the absolute value signs:

-z + 6 - (-z + 5)

Distribute the negative sign:

-z + 6 + z - 5

-z + z = 0 which leaves:

6 - 5

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3 years ago

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