Answer:
x = 20
I am not sure if you wanted the answer. Sorry!
Step-by-step explanation:
Let's solve your equation step-by-step.
1/10 x + 5 = - 3x - 13 + 4x
Step 1: Simplify both sides of the equation.
1/10 x + 5 = - 3x - 13 + 4x
1/10 x + 5 = - 3x + - 13 + 4x
1/10 x + 5 = (<em>- 3x + 4x</em>) + (- 13)
1/10 x + 5 = <em>x</em> + - 13
1/10 x + 5 = x - 13
Step 2: Subtract x from both sides.
1/10 x + 5 - <em>x </em>= x - 13 - <em>x</em>
- 9/10 x + 5 = - 13
Step 3: Subtract 5 from both sides
- 9/10 x + 5 - <em>5</em> = - 13 - <em>5</em>
- 9/10 x = - 18
Step 4: Multiply both sides by 10/(- 9).
(<em>10/ - 9</em>) * (- 9/10 x) = (<em>01/ - 9</em>) * (- 18)
x = 20
Hope this helps!
Answer:
x
Step-by-step explanation:
7x+18−6(x+1)−12
start out with distributive property
7x+18+(-6x)+(-6)+(-12)
then add the common things together
x+0
answer is just x, or infine answers, you could put in anything for x
<h3>
Answer: Choice D) </h3>
More members prefer a beach vacation and ski vacation than an adventure vacation.
======================================================
Explanation:
Let's go through the four answer choices to see which one is true.
- Choice A is false because most members prefer a cruise, as 70+72 = 142 is the largest column sum.
- Choice B is false for the same reasoning as choice A.
- Choice C is false. We have 6+1 = 7 people who prefer adventure and 19+21 = 40 who prefer to ski, giving 7+40 = 47 people who prefer either. But this is nowhere near 142 we found back in choice A above. So more people prefer a cruise than the combined amount for adventure and ski.
- Choice D is true. Adding the column totals for "beach" and "ski" gives (5+6)+(19+21) = 11+40 = 51, and this exceeds the column total of "adventure (6+1 = 7).
Answer:
The area of the circle is 
Step-by-step explanation:
we know that
A circle has a sector with area 
and central angle of 60 degrees
The area of a complete circle subtends a central angle of 
so
using proportion
Find the area of the circle
The anser is 40
the resense is verticle angle are congrounent.
