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Nikitich [7]
3 years ago
12

there are 13 animals in the barn. some are chickens and some are pigs. there are 40 legs in all. how many of each animal are the

re?
Mathematics
2 answers:
madreJ [45]3 years ago
6 0
C=chicken
p=pigs
c+p=13~p=13-c (plug in)
2c+4p=40
2c+4(13-c)=40
2c+52-4c=40
-2c=-12
c=6
6+p=13
p=7
6 chickens
7 pigs
attashe74 [19]3 years ago
5 0
Let p = pigs 
and c = chickens 

p + c = 13  ( this is the total number of animals in the barn) 

chicken have 2 legs and pigs have 4 legs 
2c + 4p = 40  ( this is the equation for the total number of legs) 

now lets solve for one variable using the first equation 

p+c = 13
p = 13 -c 

now lets plug that in the 2nd equation
 
2c+4p = 40
2c + 4(13-c) = 40 
2c + 52 - 4c = 40 
now we reduce

-2c = -12

c = 6 
so there are 6 chickens now lets find how many pigs there are by plugging into our first equation

p+6 = 13
p = 7 

so there are 6 chickens and 7 pigs
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