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2 years ago

Write the missing number. (a) 10 more than 23 is

Mathematics

2 answers:

Lelechka [254]2 years ago

4 0

33 since if you add 10 to 23 it would be 33.

Inessa05 [86]2 years ago

3 0

Answer:

Step-by-step explanation:

10+23 according to my sense

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Please help me! I can’t find the right equation. <br><br> Thank you!!

777dan777 [17]

Y=mx+c where m is the gradient.
If the equation is perpendicular is - $\frac{3}{4}$

Use y-y1=m(x-x1)
and you should get
y+1=- $\frac{3}{4}$ (x+4)
4y+4=-3x-12
y=-<span> $\frac{3}{4}$ </span>x - 16

3 0

2 years ago

There are 400 people in a talent show in middle school in February 62% of students performed in the band concert how many studen

grandymaker [24]

Answer:

62% of 400 = 248

Step-by-step explanation:

62% of 400 = 0.62 × 400 = 248

7 0

2 years ago

James traveled 153 miles in 2 hours. If he continues at a constant speed, how many miles can

Pachacha [2.7K]

Answer:

612

Step-by-step explanation:

take 153 and 2 and divide

153/2=76.5

This answer is your rate in mph, so now take this and multiply by hours given

76.5*8=612 use a calculator.

7 0

2 years ago

1. On each triangle, draw a segment to represent the height that corresponds to the given base.

Semenov [28]

Answer:

YY;UU

Step-by-step explanation:

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6 0

2 years ago

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

2 years ago