Answer:
<h2>22 hours and 10 hours </h2>
Step-by-step explanation:
let the jobs be x and y, so that
x+y=32--------1
9x+7y=248----2
x=32-y
substitute x=32-y for x in equation 2 we have
9(32-y)+7y=248
open bracket we have
288-9y+7y=248
-2y=248-288
-2y=-40
2y=40
divide both sides by 2 we have
y=40/2
y= 10 hours
subtitute y=10 for y in equation 1 to find x
x+10=32--------1
x=32-10
x=22
x=22 hours
The correct answer here would be D. -1(3x+1)(x+5). You can find this answer by redistributing the problem.
-1(3x+1)(x+5)
-1(3x²+15x+1x+5)
-1(3x²+16x+5)
-3x²-16x-5
Using the math above, we can see that when we redistribute we get the original equation. That makes Choice D correct.
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
5 can stay as is, but 5503 can be rounded to 5500 so 5500x5=27500