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Zinaida [17]
3 years ago
15

Calculate the value of6+(12245 - 1)​

Mathematics
2 answers:
defon3 years ago
5 0
6+(12245-1)
6+12244
Answer: 12250
Dafna11 [192]3 years ago
3 0

Answer:

12250

Step-by-step explanation:

6 + (12245-1)

6 + 12244

12250

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In triangle ABC, c = 3, ∠A = 63°, and ∠C = 49°. Find a
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Answer:

a = 3.5

Step-by-step explanation:

\frac{a}{sin(A)}  = \frac{c}{sin(C)} \\\\a = \frac{csin(A)}{sin( C )} \\\\a = \frac{3 sin(63^{o} )}{sin(49^{o} )} \\\\a = 3.5

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Find the arc length of the semicircle.
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I think it’s 15.71
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Charlie bought a 2and 1 half bag of oranges for $3.75.What is the cost of one pound of oranges?
Nikolay [14]
Charlie buys 2.5 pounds of oranges for 3.75.

To find out how much he will pay for 1 pound of oranges, use the proportion

2.5/3.75 = 1/x
Cross multiply to get x = $1.50 per pound of oranges.
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3 years ago
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1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
4 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
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