Answer:
The last one
Step-by-step explanation:
f(2) = 4x-5 = 3
f(-4) = 4x - 5 = -21
F(2) has a greater value than f(-4)
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
Answer:
a =12*sqrt(2)
Step-by-step explanation:
3. The Pythagorean theorem states
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 +21^2 = 27^2
a^2 +441 =729
Subtract 441 from each side
a^2 +441-441 = 729 -441
a^2 =288
Take the square root of each side
sqrt(a^2) = sqrt(288)
sqrt(xy) = sqrt(x)sqrt(y)
a = sqrt(144)sqrt(2)
a =12*sqrt(2)
Answer:
B
Step-by-step explanation:
Points A,B ,C are all to the left of 0 so they are negative
We want a point -3 1/2
The points A and B are to the left of -3 so they are more negative than -3
A is at -5 so it cannot be -3 1/2
