The length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other. The area of a rectangle is:
Area = length * width
From the image:
Length of AB = x + 4
Length of BC = x + 6
The area of rectangle ABCD = Length of AB * Length of BC
28 = (x + 4)(x + 6)
x² + 10x + 24 = 28
x² + 10x = 4
Comparing with x² + ax = b gives:
a = 10, b = 4
Therefore the length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
Find out more at: brainly.com/question/15019502
Answer:
A= 0,2
B= 0,2
C= 0,4
D=0,2
Step-by-step explanation:
We know that only one team can win, so the sum of each probability of wining is one
P(A)+P(B)+P(C)+P(D)=1
then we Know that the probability of Team A and B are the same, so
P(A)=P(B)
And that the the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)
Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2
Now if we use the first formula:
P(A)+P(B)+P(C)+P(D)=1
P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1
0,5 P(A)+0.9=1
0,5 P(A)= 0,1
P(A)= 0,2
P(B)= 0,2
P(C)=0,4
P(D)=0,2
Answer:
a. Yes
b. No
Step-by-step explanation:
To find if an ordered pair is a solution to the inequality, substitute its x and y values for the x and y in the inequality and solve. If the equation is true, then it is a solution. If it is not, then it is not a solution.
1) First, substitute the x and y values of (3, 1) into the inequality. So, substitute 3 for x and 1 for y:
1 is greater than or equal to 1, so (3,1) is a solution.
2) Second, do the same with the point (1, -4). Substitute 1 for x and -4 for y:
However, -4 is not greater than or equal to -3, thus (1, -4) is not a solution.
Answer:
The order is "D, B, A, E, C".
Step-by-step explanation:
The numbers are as follows:
![A=\frac{2^{1/2}}{4^{1/6}}\\\\B = \sqrt[12]{128}\\\\C=(\frac{1}{8^{1/5}})^{2}\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B4%5E%7B1%2F6%7D%7D%5C%5C%5C%5CB%20%3D%20%5Csqrt%5B12%5D%7B128%7D%5C%5C%5C%5CC%3D%28%5Cfrac%7B1%7D%7B8%5E%7B1%2F5%7D%7D%29%5E%7B2%7D%5C%5C%5C%5CD%20%3D%20%5Csqrt%7B%5Cfrac%7B4%5E%7B-1%7D%7D%7B2%5E%7B-1%7D%5Ccdot%208%5E%7B-1%7D%7D%7D%5C%5C%5C%5CE%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B1%2F2%7D%7D%5Ccdot%204%5E%7B-1%2F4%7D)
Simplify the value of A, B, C, D and E as follows:
![A=\frac{2^{1/2}}{4^{1/6}}=\frac{2^{1/2}}{2^{2/6}}=\frac{2^{1/2}}{2^{1/3}}=2^{1/2-1/3}=2^{1/6}=1.1225\\\\B = \sqrt[12]{128}=(128)^{1/12}=(2^{7})^{1/12}=2^{7/12}=1.4983\\\\C=(\frac{1}{8^{1/5}})^{2}=(\frac{1}{(2^{3})^{1/5}})^{2}=(\frac{1}{2^{3/5}})^{2}=\frac{1}{2^{3/5\times2}}=\frac{1}{2^{6/5}}=2^{-6/5}=0.4353\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}=\sqrt{\frac{2^{-2}}{2^{-1}\cdot 2^{-3}}}=\sqrt{2^{-2+1+3}}=2\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}= (2^{1/2})^{1/3}\cdot 2^{-2/4}=2^{-1/3}=0.7937](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B4%5E%7B1%2F6%7D%7D%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B2%5E%7B2%2F6%7D%7D%3D%5Cfrac%7B2%5E%7B1%2F2%7D%7D%7B2%5E%7B1%2F3%7D%7D%3D2%5E%7B1%2F2-1%2F3%7D%3D2%5E%7B1%2F6%7D%3D1.1225%5C%5C%5C%5CB%20%3D%20%5Csqrt%5B12%5D%7B128%7D%3D%28128%29%5E%7B1%2F12%7D%3D%282%5E%7B7%7D%29%5E%7B1%2F12%7D%3D2%5E%7B7%2F12%7D%3D1.4983%5C%5C%5C%5CC%3D%28%5Cfrac%7B1%7D%7B8%5E%7B1%2F5%7D%7D%29%5E%7B2%7D%3D%28%5Cfrac%7B1%7D%7B%282%5E%7B3%7D%29%5E%7B1%2F5%7D%7D%29%5E%7B2%7D%3D%28%5Cfrac%7B1%7D%7B2%5E%7B3%2F5%7D%7D%29%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B2%5E%7B3%2F5%5Ctimes2%7D%7D%3D%5Cfrac%7B1%7D%7B2%5E%7B6%2F5%7D%7D%3D2%5E%7B-6%2F5%7D%3D0.4353%5C%5C%5C%5CD%20%3D%20%5Csqrt%7B%5Cfrac%7B4%5E%7B-1%7D%7D%7B2%5E%7B-1%7D%5Ccdot%208%5E%7B-1%7D%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%5E%7B-2%7D%7D%7B2%5E%7B-1%7D%5Ccdot%202%5E%7B-3%7D%7D%7D%3D%5Csqrt%7B2%5E%7B-2%2B1%2B3%7D%7D%3D2%5C%5C%5C%5CE%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B1%2F2%7D%7D%5Ccdot%204%5E%7B-1%2F4%7D%3D%20%282%5E%7B1%2F2%7D%29%5E%7B1%2F3%7D%5Ccdot%202%5E%7B-2%2F4%7D%3D2%5E%7B-1%2F3%7D%3D0.7937)
Arrange the following numbers in increasing order as follows:
D > B > A > E > C
Thus, the order is "D, B, A, E, C".
