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emmainna [20.7K]
3 years ago
5

PLS HELP ASAP I WILL GIVE BRAINERLIST PLUS 15 POINTS

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

a

Step-by-step explanation:

1 3/7 equals about 1.43

with that in mind least to greatest is:

1.38, 1.4, 1 3/7

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The area of rectangle ABCD is 28 cm^2
Sonbull [250]

The length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4

A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other. The area of a rectangle is:

Area = length * width

From the image:

Length of AB = x + 4

Length of BC = x + 6

The area of rectangle ABCD = Length of AB * Length of BC

28 = (x + 4)(x + 6)

x² + 10x + 24 = 28

x² + 10x = 4

Comparing with x² + ax = b gives:

a = 10, b = 4

Therefore the length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4

Find out more at: brainly.com/question/15019502

8 0
2 years ago
Four teams A,B,C, and D compete in a tournament, and exactly one of them will win the tournament. Teams A and B have the same ch
beks73 [17]

Answer:

A= 0,2

B= 0,2

C= 0,4

D=0,2

Step-by-step explanation:

We know that only one team can win, so the sum of each probability of wining  is one

P(A)+P(B)+P(C)+P(D)=1

then we Know that the probability of Team A and B are the same, so

P(A)=P(B)

And that the  the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)

Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2

Now if we use the first formula:

P(A)+P(B)+P(C)+P(D)=1

P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1

0,5 P(A)+0.9=1

0,5 P(A)= 0,1

P(A)= 0,2

P(B)= 0,2

P(C)=0,4

P(D)=0,2

4 0
3 years ago
Is the ordered pair a solution of y ≥ 2x − 5? a. (3, 1) b. (1, −4)
Deffense [45]

Answer:

a. Yes

b. No

Step-by-step explanation:

To find if an ordered pair is a solution to the inequality, substitute its x and y values for the x and y in the inequality and solve. If the equation is true, then it is a solution. If it is not, then it is not a solution.

1) First, substitute the x and y values of (3, 1) into the inequality. So, substitute 3 for x and 1 for y:

1 \geq 2(3)-5\\1\geq 6-5\\1\geq 1

1 is greater than or equal to 1, so (3,1) is a solution.

2) Second, do the same with the point (1, -4). Substitute 1 for x and -4 for y:

-4\geq 2(1)-5\\\\-4\geq 2-5\\-4\geq -3

However, -4 is not greater than or equal to -3, thus (1, -4) is not a solution.

4 0
3 years ago
Arrange the following numbers in increasing order: \begin{align*} A &= \frac{2^{1/2}}{4^{1/6}}\\ B &= \sqrt[12]{128}\vph
prisoha [69]

Answer:

The order is "D, B, A, E, C".

Step-by-step explanation:

The numbers are as follows:

A=\frac{2^{1/2}}{4^{1/6}}\\\\B = \sqrt[12]{128}\\\\C=(\frac{1}{8^{1/5}})^{2}\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}

Simplify the value of A, B, C, D and E as follows:

A=\frac{2^{1/2}}{4^{1/6}}=\frac{2^{1/2}}{2^{2/6}}=\frac{2^{1/2}}{2^{1/3}}=2^{1/2-1/3}=2^{1/6}=1.1225\\\\B = \sqrt[12]{128}=(128)^{1/12}=(2^{7})^{1/12}=2^{7/12}=1.4983\\\\C=(\frac{1}{8^{1/5}})^{2}=(\frac{1}{(2^{3})^{1/5}})^{2}=(\frac{1}{2^{3/5}})^{2}=\frac{1}{2^{3/5\times2}}=\frac{1}{2^{6/5}}=2^{-6/5}=0.4353\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}=\sqrt{\frac{2^{-2}}{2^{-1}\cdot 2^{-3}}}=\sqrt{2^{-2+1+3}}=2\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}= (2^{1/2})^{1/3}\cdot 2^{-2/4}=2^{-1/3}=0.7937

Arrange the following numbers in increasing order as follows:

D > B > A > E > C

Thus, the order is "D, B, A, E, C".

7 0
2 years ago
What is the value of the y coordinate of point A
Morgarella [4.7K]

Answer:

There is no picture.

5 0
3 years ago
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