Question

For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.^2. What should he do to the dimensions in order to have a similar rectangle that's area is only 2 in.^2?
options:

Divide them by nine.

Divide them by six.

Divide them by three.

Multiply them by three.

Answer 1

We have to divide the dimensions by 9 to get a similar rectangle that's area is only 2 in.^2

Solution:

Given that,

For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.^2

In order to have a similar rectangle that's area is only 2 in.^2

Thus, we need to find the scale factor

Let "c" be the scale factor

Let "x" be the area of original rectangle

Let "y" be the area of dilated rectangle

Therefore,

$c = \frac{y}{x}\\\\c = \frac{2}{18}\\\\c = \frac{1}{9}$

Therefore, we have to divide the dimensions by 9 to get a similar rectangle that's area is only 2 in.^2

Answer 2

Answer:

Divide them by three.