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3 years ago

11

For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.^2. What should he do to the dimensions in

order to have a similar rectangle that's area is only 2 in.^2?
options:

Divide them by nine.

Divide them by six.

Divide them by three.

Multiply them by three.

2 answers:

san4es73 [151]3 years ago

8 0

We have to divide the dimensions by 9 to get a similar rectangle that's area is only 2 in.^2

<em><u>Solution:</u></em>

Given that,

For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.^2

In order to have a similar rectangle that's area is only 2 in.^2

Thus, we need to find the scale factor

Let "c" be the scale factor

Let "x" be the area of original rectangle

Let "y" be the area of dilated rectangle

Therefore,

$c = \frac{y}{x}\\\\c = \frac{2}{18}\\\\c = \frac{1}{9}$

Therefore, we have to divide the dimensions by 9 to get a similar rectangle that's area is only 2 in.^2

lapo4ka [179]3 years ago

4 0

Answer:

Divide them by three.

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Dean Halverson recently read that full-time college students study 20 hours each week. She decides to do a study at her universi

romanna [79]

Answer: The p-value is 0.154.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis :

$H_0:\mu=20$

Alternate hypothesis :

$H_1:\mu$

Population mean = 20 hours

Sample mean = 18.5 hours

Sample standard deviation = 4.3 hours

Sample size n = 35

So, test statistic would be

$z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{18.5-20}{\dfrac{4.3}{\sqrt{35}}}\\\\z=\dfrac{-1.5}{0.726}\\\\z=-2.066$

So, the p value would be 0.154.

Hence, the p-value is 0.154.

4 0

3 years ago

Evaluate g(n-7) if g(x) =x^2-5 / 3x

aleksandrvk [35]

Answer:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

Step-by-step explanation:

The given function is

$g(x)=\frac{x^2-5}{3x}$

To find g(n-7), we substitute x=n-7 to obtain;

$g(n-7)=\frac{(n-7)^2-5}{3(n-7)}$

Expand the parenthesis to obtain;

$g(n-7)=\frac{n^2-14n+49-5}{3n-21}$

Simplify:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

7 0

3 years ago

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th

Vesna [10]

Question is Incomplete; Complete question is given below;

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and the distance she rides is represented by the variable d. Which statements are true of the scenario? Check all that apply.

a. The independent variable, the input, is the variable d, representing distance.

b. The distance traveled depends on the amount of time Marlene rides her bike.

c. The initial value of the scenario is 16 miles per hour.

d. The equation t = d + 16 represents the scenario.

e. The function f(t) = 16t represents the scenario.

Answer:

OPTION (b) and (e) are the true statements.

Step-by-step explanation:

Given:

$t=>$ time in hours that she rides

$d=>$ distance she rides

We have to find the statements that are true of the scenario.

Solution:

$d=16t$

The equation itself is a linear equation which presents an equation's scenario and time (t) is a independent variable and distance (d) is a dependent variable.

Equation for distance according to function is $f(t)=16t$

Here, we can use graph tool, you can see the attested image below.

Function's domain is the interval⇒ [0,∞)

$t\geq0$

Function's range is the interval⇒ [0,∞)

$f(t)\geq0$

The statements which are TRUE are explained below :

b) The distance traveled depends on the amount of time Marlene rides her bike

It is true because as explained above that equation for distance according to function is $f(t)=16t$

e) The function f(t) = 16t represents the scenario.

It is true because as explained that the scenario has been represented by the function above that $f(t)=16t$

* The statement (a) is false because the variable t is the independent variable.

* The statement (c) is false because $16$ is been represented as the slope or the rate of the linear equation.

* The statement (d) is false because $t = d + 16$ donot represents the scenario.

8 0

2 years ago

manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin

alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) $nCr q^{r} p^{n-r}$

$nCr = \frac{n!}{(n-r)!r!}$

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = $20C18 * 0.97^{18} * 0.03^{20-18}$

P(X=18) = $20C18 * 0.97^{18} * 0.03^{2}$

P(X=18) = 0.0988

P(X=19) = $20C19 * 0.97^{19} * 0.03^{20-19}$

P(X=19) = $20C19 * 0.97^{19} * 0.03^{1}$

P(X=19) = 0.3364

P(X=20) = $20C20 * 0.97^{20} * 0.03^{20-20}$

P(X=20) = $20C20 * 0.97^{20} * 0.03^{0}$

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0

3 years ago

4x + 6 = 8x – 10 graphing

DIA [1.3K]

Are you graphing or trying to find the answer

8 0

3 years ago

Read 2 more answers