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Black_prince [1.1K]
3 years ago
14

Joe has read 30% of a book. He has 49 more pages to finish. How many pages are there in the book?

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

70 pages

Step-by-step explanation:

100%-30%=70%

70% of the book is 49 pages.

x is the total number of pages.

0.7x=49

7x=490

x=70

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Which equation has the components of 0 = x2 – 9x – 20 inserted into the quadratic formula correctly?
Aneli [31]

Answer:

The required equation is x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}.

Step-by-step explanation:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

The given quadratic equation is

x^2-9x-20=0

Here, a=1, b=-9 and c=-20.

Substitute a=1, b=-9 and c=-20 in the above quadratic formula.

x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}

Therefore the required equation is x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}.

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Answer:3/8

Step-by-step explanation:

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Step-by-step explanation:

 

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Write the equation in slope-intercept form and find the equation of a line through the given point (a) parallel and (b) perpendi
skelet666 [1.2K]

keeping in mind that parallel lines have the same exact slope, hmmm what's the slope of 4x - 2y = 3 anyway?  well, let's put it in slope-intercept form firstly.


\bf 4x-2y=3\implies 4x-3=2y\implies \cfrac{4x-3}{2}=y
\\\\\\
\cfrac{4x}{2}-\cfrac{3}{2}=y\implies \stackrel{slope}{2}x-\cfrac{3}{2}=y


a)


so we're looking for a line whose slope is 2 and passes through 2,1.


\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})~\hspace{10em}
slope = m\implies 2
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=2(x-2)
\\\\\\
y-1=2x-4\implies \blacktriangleright y=2x-3 \blacktriangleleft


b)


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{\stackrel{slope}{2\implies \cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})~\hspace{10em}
slope = m\implies -\cfrac{1}{2}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-\cfrac{1}{2}(x-2)
\\\\\\
y-1=-\cfrac{1}{2}x+1\implies \blacktriangleright y=-\cfrac{1}{2}x+2 \blacktriangleleft

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Vedmedyk [2.9K]

Answer:

y=x +3

Step-by-step explanation:

this is the equation because it shows the actual relationship between x and y

6 0
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