Answer:
E ( 1 , -1 ) is in quadrant IV
PEMDAS
2.5x + 0.1x = 2.6x
2.6x - 0.01x = 2.59x
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer: 0 -4 and -8
Step-by-step explanation:
If you divide -12/-3=4 and 4/4=1
First, the factor pairs for 18 are:
1, 18
2, 9
3, 6
Since the middle term is -3, the two factors must be 3 apart. The only pair that is 3 values apart is 3, 6.
Since the middle value is negative, the larger number is negative. This means that the 6 is negative.
z = -6
z = 3
Set each equal to 0;
z = -6
z + 6 = 0
z = 3
z - 3 =0
So your factors are (z+6) and (z-3), or answer B.