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qwelly [4]
3 years ago
8

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPHEL

Mathematics
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

15 degrees

Step-by-step explanation:

90-75= 15

........

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Consider the equation below.
m_a_m_a [10]

The correct equation that can be used is (t+4)^{2}=3 ( Option A)

<u>Step-by-step explanation:</u>

Given Equation:

4 t^{2}-28 t=6 t^{2}-12 t+26

It can be rearranged as follows,

6 t^{2}-4 t^{2}+28 t-12 t+26=0

IT can be simplified as,

2 t^{2}+16 t+26=0

Dividing the above equation by 2, we will get,

t^{2}+8 t+13=0

Now we have to divide the coefficient of t by 2, we will get 4 and squaring 4, and add that value on both sides of the equation we will get,

t^{2}+8 t+16=-13+16

t^{2}+8 t+16=3

3 0
3 years ago
The top angle of a right triangle has tan 0=2√2. what is cos 0?
mariarad [96]

Answer:

Learn to find the sine, cosine, and tangent of 45-45-90 triangles and also ... Until now, we have used the calculator to evaluate the sine, cosine, and tangent of an angle. However, it is possible to evaluate the trig functions for certain angles without ... This is because there are two special triangles whose side ratios we know!

Step-by-step explanation:

4 0
3 years ago
How do i do 15, 16???
a_sh-v [17]
  • It's very long so I'm not giving answers but here's how i would do it:
  1. use Pythagoras a^2 +b^2 = c^2 where c is the longest side
  2. use sine rule \frac{a}{sin(A)} = \frac{b}{sin(B)} = \frac{c}{sin(C)} where lower cases are the sides, and capitals are their opposite angles.

e.g for 15:

a = 3, b is missing, c = 10

A is missing, B is ?, C is 90

3 0
2 years ago
What is the value of n in this equation?<br><br> n - 409 = 732
Natalija [7]

Answer:

n = 1141

Step-by-step explanation:

To find the value of n you add 732 and 409 giving you 1141.

8 0
3 years ago
Read 2 more answers
Four batsmen on a cricket team had a mean of 42.5 runs the other 7 batsmen had a mea of 18 what was the mean number of scored by
Ira Lisetskai [31]

Answer:

The mean score of the entire team is 26.909.

Step-by-step explanation:

Given that four batsmen had a mean of 42.5.

Let $ \textbf{B}_{\textbf{i} $, where $ i = 1, 2, 3, \hdots, 11 $ denote the batsmen.

From the first statement, we have:

$ \frac{B_1 + B_2 + B_3 + B_4}{4} = 42.5 $

$ \implies B_1 + B_2 + B_3 + B_4 = 42.5 \times 4 =  \textbf{170} $

Therefore, the sum of the scores of the first four batsmen is 170.

Now, from the second statement we have:

$ \frac{B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{7} = 18 $

$ \implies B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11} = 18 \times 7 = \textbf{126} $

That is, the sum of the scores of the remaining 7 batsmen is 126.

Now, to calculate the average(mean) of the entire team, we add the individual scores and divide it by 11.

$ \implies \frac{B_1 + B_2 + B_3 + B_4 + B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{11} = \frac{170 + 126}{11} $

$ = \frac{296}{11} $

$ = \textbf{26.90} $ which is the required answer.

8 0
3 years ago
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