Answer:
a) 0.0977
b) 0.3507
c) No it is not unusual for a broiler to weigh more than 1610 grams
Step-by-step explanation:
Mean = 1395 grams
Standard deviation = 200 grams. Use the TI-84 Plus calculator to answer the following.
We solve using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
(a) What proportion of broilers weigh between 1160 and 1250 grams?
For x = 1160
z = 1160 - 1395/300
= -0.78333
Probability value from Z-Table:
P(x = 1160) = 0.21672
For x = 1250 grams
z = 1250 - 1395/300
z = -0.48333
Probability value from Z-Table:
P(x = 1250) = 0.31443
The proportion of broilers weigh between 1160 and 1250 grams is
0.31443 - 0.21672
= 0.09771
≈ 0.0977
(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?
For x = 1510
= z = 1510 - 1395/300
z = 0.38333
Probability value from Z-Table:
P(x<1510) = 0.64926
P(x>1510) = 1 - P(x<1510) = 0.35074
Approximately = 0.3507
(c) Is it unusual for a broiler to weigh more than 1610 grams?
For x = 1610
= z = 1610 - 1395/300
z = 0.71667
Probability value from Z-Table:
P(x<1610) = 0.76321
P(x>1610) = 1 - P(x<1610) = 0.23679
No it is not unusual for a broiler to weigh more than 1610 grams
