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4 years ago

Anyone can help with the graph to find the domain and range ?

Mathematics

1 answer:

marusya05 [52]4 years ago

6 0

Answer:

The domain = - 4,-2,-1,4

Range = -4,-1,0,1

Step-by-step explanation:

Domain is the set of all x-values.

Range is the set of all y-values.

The first left point is at x = -4 and y = - 4. The domain is x = - 4. The range is y = - 4.

For domain, we focus only x-axis/term and value.

For range, we focus only y-axis/term and value.

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Tan 45°. tan² 30° tan 60° slove it

makvit [3.9K]

Answer:

$\frac{\sqrt{3} }{3} or \frac{1}{\sqrt{3} }$

Step-by-step explanation:

We can break the problem into three parts,

tan45 = sin(45)/cos(45)= $\frac{\frac{\sqrt{2}}{2} }{\frac{\sqrt{2}}{2} } =1$

$tan^{2}30 =(tan30))^{2}=(sin30/cos30)^2=((1/2)/(\sqrt{3}/2))^2 =(1/\sqrt{3})^2$

$tan60=sin60/cos60=\frac{\sqrt{3}/2 }{1/2} =\sqrt{3}$

Then, $tan45*tan^230*tan60=1*(1/sqrt(3))^2*sqrt(3)=1/sqrt(3)=sqrt(3)/3$

Therefore, the solution is sqrt(3)/3

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2 years ago

.Arrange in decreasing order 1/2, 2/3, 5/8, 3/4

Hatshy [7]

Answer:

5/8, 3/4, 2/3, 1/2

Step-by-step explanation:

8 is more than 4, 4 is more than 3, 3 is more than 2.

4 0

3 years ago

Read 2 more answers

Suppose that y varies directly with x , and =y24 when =x15 .

Lunna [17]

If I answer can I have brainliest answer plz

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4 years ago

1) (9,- 4) and (1,8) are thecoordinates of the endpoints of a diameter of a circle. Write the

gizmo_the_mogwai [7]

Answer:

(x-5)²+(y-2)²=52

Step-by-step explanation:

first find the midpoint (center of the circle)

(9+1)/2, (-4+8)/2

(5, 2) = center

then distance formula to find diameter

√(9-1)²+(-4-8)²=√64+144 = √208 = 2√52

The radius is half the diameter = √52

Formula for circle is (x-h)²+(y-k)²=r², where (h, k) is the center

Now you can plug everything in.

(x-5)²+(y-2)²=52

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4 years ago

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Ierofanga [76]

Answer:

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Step-by-step explanation:

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3 years ago