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Irina-Kira [14]
3 years ago
10

If five kids sit on a d and one has an orgasm how many are still going

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0

Answer:

jesus...you're twisted anyway 69 :)

Step-by-step explanation:

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Question 2
cluponka [151]

Answer:

4:5

Step-by-step explanation:

28:35

28/7:35/7

4:5

hopefully this helps :)

4 0
3 years ago
How many lines can be constructed perpendicular to AC that pass through point D?
Vladimir [108]

Answer:

1

Step-by-step explanation:

This is the answer by definition.

5 0
2 years ago
13 POINTS IF YOU ANSWER!!!
Whitepunk [10]
H: 5 square yards is the correct answer, break the figure into squares and then multiply length by width to get area
6 0
3 years ago
Simplify 2m - [n - (m - 2n)]. -3m - n 3m - n -3m - 3n 3m - 3n
zhenek [66]

Answer:

3m-3n

Step-by-step explanation:

We want to simplify the expression;

2m - [n - (m - 2n)].

We expand the parenthesis to obtain;

2m - (n - m + 2n)

2m - ( - m + 3n)

Expand further to get;

2m +m -3n

Combine the first two terms;

3m-3n

4 0
4 years ago
Read 2 more answers
A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis
VMariaS [17]

Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

8 0
3 years ago
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