Answer:
- The function is injective but nor surjective
Step-by-step explanation:
<u>We see that:</u>
<u>For any x₁ and x₂ ∈ N, </u>
- f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers
It it confirmed one-to-one, hence it is injective
<u>Check the surjectivity:</u>
f(x) = y ∈ N
<u>Let y = 2, then:</u>
Since x is not natural, the function is not surjective
28 in^2
Divide shape into one rectangle and two squares:
Area of rectangle:
10 x 2 = 20 in^2
Area of one square:
2 x 2 = 4 in^2
Multiply that by 2 because we have 2 squares similar in size:
4 in^2 x 2 = 8 in^2
Add the area of the rectangle and two squares:
20 in^2 + 8 in^2 = 28 in^2
Have a nice day
Hope this helps!
No, it is an irrational number. It repeats
No, it is an irrational number because it does not terminate/end
The modulus of complex number can be computed with this equation:
|z|=sqrt(Re(z)^2+Im(z)^2)
z = -2-6i
Re(z)=-2, so Re(z)^2=4
Im(z)=-6, so Im(z)^2=36
|z|=sqrt(36+4)=sqrt(40)=6.3
Answer:
3.125
Step-by-step explanation: