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2 years ago

7

What 2 numbers are between 8.43 and 8.437

1 answer:

balandron [24]2 years ago

3 0

Answer:

um,i think its 8.435 and 8.46

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PLS HELP ME FINISH THIS THANKS

Y_Kistochka [10]

Pay attention to the even numbers

8 0

2 years ago

Tributive Property<br>each of the following. Show for what val<br>x - 2(x - 2) =<br>X

levacccp [35]

Answer:

Step-by-step explanation:

Subtraction is not commutative. For example, 4 − 7 does not have the same difference as 7 − 4. The − sign here means subtraction.

However, recall that 4 − 7 can be rewritten as 4 + (−7), since subtracting a number is the same as adding its opposite. Applying the commutative property for addition here, you can say that 4 + (−7) is the same as (−7) + 4. Notice how this expression is very different than 7 – 4.

4 0

2 years ago

Question 3 (2 points)

Sveta_85 [38]

I believe the answer is a

5 0

2 years ago

Find the first five terms of the recursive sequence <br> an=-6an-1 where a1=4.5

grandymaker [24]

Answer:

4.5, -27, 162,-972, 5832

Step-by-step explanation:

The given recursive definition is,

$a_n=-6a_{n-1}, a_1=4.5$

This will form a geometric sequence with first term 4.5 and common ratio r=-6.

When n=2, we have:

$a_2=-6a_1 \\ \implies \: a_2=-6 \times 4.5 = - 27$

When n=3, we get:

$a_3=-6a_2 \\ \implies \: a_3=-6 \times - 27 = 162$

When n=4, we get:

$a_4=-6a_3 \\ \implies \: a_4=-6 \times 162 = - 972$

When n=5, we get:

$a_5=-6a_4 \\ \implies \: a_5=-6 \times - 972 = 5832$

Therefore the first five terms are:

4.5, -27, 162,-972, 5832

3 0

2 years ago

How to solve the system of equation 500y-600x=2800 , 400y-400x=2400 by elimination

tatiyna

Answer:

$x=2$ and $y=8$

Step-by-step explanation:

Given:

Equation 1:

$500y-600x=2800$

Simplifying the above equation by dividing both sides by 100

$\frac{500y-600x}{100}=\frac{2800}{100}$

$\frac{500y}{100}-\frac{600x}{100}=28\\\\5y-6x=28$

Equation 2:

$400y-400x=2400$

Simplifying the above equation by dividing both sides by 400.

$\frac{400y-400x}{400}=\frac{2400}{400}$

$\frac{400y}{400}-\frac{400x}{400}=6\\\\y-x=6$

Now the system of equation is:

(1a) $5y-6x=28$

(2a) $y-x=6$

Solving by elimination

Multiplying equation (2a) with $-5$

$-5(y-x)=-5\times 6$

(2b) $-5y+5x=-30$

Adding equations (1a) and (2b) in order to eliminate $y$

$5y-6x=28$

+ $-5y+5x=-30$

We get $-x=-2$

∴ $x=2$

Plugging $x=2$ in equation (2a).

$y-2=6$

Adding $2$ both sides.

$y-2+2=6+2$

∴ $y=8$

7 0

2 years ago