Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Y = 7x^2-3
x=7y^2-3
.......................
Variable
Step-by-step explanation:
Answer:
Part A: The total is 57.58
Part B: 19.19 each
Step-by-step explanation:
Part A: 15(3) +3.50(3)=55.50
55.50 plus the 3.75% tip (not really addition i dont know how to find a percentage so i looked that part up) but it come out to $57.58
Part B: 57.58 divided by 3 is $19.19 ( I do 3 because Maria and 2 more friends)
Hope it helps and that it is 100% correct dont come at me if something is wrong with my math