Answer:
In a homozygous state, the allele "P" is lethal. Those individuals with PP genotype will be born dead.
Explanation:
The allele P is dominant over p and expresses the trait "platinum". But in the homozygous state, it is mortal, PP. The allele p expresses the "Silver" trait.
This is:
- For platinum individuals, the genotype should be Pp
- For silver individuals, the genotype should be pp
- For dead individuals, the genotype should be PP.
So in the crosses, the punnet squares are:
1- Silver x Silver
Parental) pp x pp
Gametes) p p p p
Punnet square)
p p
p pp pp
p pp pp
F1 Genotype) 100 % recessive homozygote pp
2- Silver x Platinum
Parental) pp x Pp
Gametes) p p P p
Punnet square)
p p
P Pp Pp
p pp pp
F1 Genotype) 50 % recessive homozygote pp,
50% heterozygote for the trait Pp
3- Platinum x Platinum
Parental) Pp x Pp
Gametes) P p P p
Punnet square)
P p
P PP Pp
p Pp pp
F1 Genotype) 25 % recessive homozygote pp
50% heterozygote for the trait Pp
25% dominant homozygote PP. This is a dead
individual.
In this last cross, individuals with genotype PP dye, so, of the whole offspring, there are two platinum for each silver offspring.
Answer:
The correct answer is - Benedict's solution for the test for glucose in food.
Explanation:
Benedict's solution is a test that is used to check if there is a presence of glucose in a food sample or not. It is possible due to the oxidation of the aldehyde present in the glucose turns to carboxylic acid in presence of the clear blue solution of sodium and copper salts or benedict's solution.
In presence of Benedict's solution the color of the sample turns yellow to orange with an increase in heat, however, the initial color of the solution is aqua blue.
Thus, the correct answer is - Benedict's solution for the test for glucose in food.
Is needed to keep most plants alive
Prophase is the first phase of mitosis, this when the nuclear envelope breaks down and the nucleuse disappears. Hope I was able to help. :)
