Answer:
a). Radius r of the small sector= 12cm
b). Perimeter of the shape= 68 cm
c). Angle= 47.7°
Step-by-step explanation:
a). Radius of the big sector= 24 cm
Arc if the big sector= 20 cm
Arc of the small sector= 10 cm
For the radius r of the small sector
r/10 = 24/20
r=(10*24)/20
r= 24/2
r= 12 cm
Radius r of the small sector= 12cm
b). Perimeter of the shape
= Total length of the shape
Let's note that the other side of the sector is also the radius= 24 cm
Perimeter= 20+24+24
Perimeter of the shape= 68 cm
c) the angle
Length of arc = 2πr*(angle/360)
Let angle = b
Length of arc = 20cm
20= 2*3.14*24*(b/360)
(20*360)/(2*3.14*24)= b
47.7°= b
Angle= 47.7°
The mean or better known as the average is all of the numbers combined and then divided by how many numbers there were. You should be able to find the mean of any set of numbers. There might be a mistake in the calculations some where.
11/36
OR
.3055555555................
hope this helped
Question s Incomplete; Complete question is given below;
There is a mound of g pounds of gravel in a quarry. Throughout the day, 400 pounds of gravel are added to the mound. Two orders of 900 pounds are sold and the gravel is removed from the mound. At the end of the day, the mound has 1,500 pounds of gravel. Write the equation that best describes the situation.
Answer:
The equation that best describes the situation is .
Step-by-step explanation:
Given:
Amount of gravel present initially = ''.
Now Given:
Throughout the day, 400 pounds of gravel are added to the mound.
So we can say that;
Amount of gravel after addition =
Also given:
Two orders of 900 pounds are sold and the gravel is removed from the mound.
Now Two orders of 900 pounds =
So we can say that;
Amount of gravel after removing =
Now Given:
Amount left in mount at the end of the day = 1300 pounds.
So we can say that;
Hence the equation that best describes the situation is .