The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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The answer is -6.825 in fraction form, it would be -6 33/40
Answer:
-35/6
Step-by-step explanation:
We need to find the value of x , And the given pair of Rational numbers are equal.
<u>Question</u><u> </u><u>(</u><u>I)</u><u> </u><u>:</u><u>-</u><u> </u>
→ 3/4 = 7/x
→ 7/x = 3/4
→ 1/x = 3/4 × 1/7
→ 1/x = 3/28
→ x = 28/3
<u>Question</u><u> (</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>
→ x/7 = -5/6
→ x = -5/6 × 7
→ x = -35/6
<h3>
• Hence the value of x is -35/6 .</h3>
