The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.
Step-by-step explanation:
The given is,
In ΔWXY, ∠Y=90°
XW = 53
YX = 28
WY = 45
Step:1
Ref the attachment,
Given triangle XWY is right angled triangle.
Trigonometric ratio's,
∅ 
For the given attachment, the trigonometric ratio becomes,
∅ 
.....................................(1)
Let, ∠X = ∅
Where, XY = 28
XW = 53
Equation (1) becomes,
∅ 
∅ = 0.5283
∅ = 
(0.5283)
∅ = 58.109°
Result:
The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.
Answer:
x = 28
m<ABC = 57°
Step-by-step explanation:
✔️(2x + 1)° + 33° = 90° (complementary angles)
Solve for x
2x + 1 + 33 = 90
Add like terms
2x + 34 = 90
2x = 90 - 34 (subtraction property of equality)
2x = 56
Divide both sides by 2
x = 28
✔️m<ABC = 2x + 1
Plug in the value of x
m<ABC = 2(28) + 1
= 56 + 1
m<ABC = 57°
The first board is approximately 0.45 the second board is approximately 0.9 and the third board is approximately 19.8
Answer:
950 miles
the problem states that Mr. Lopez drove 77 more miles so just add 873+77 to get 950 miles
Find the perimeter of the circle is the same as finding the circumference of the circle.
Circumference Formula: C = 2πr
Divide the diameter by 2 to find the radius.
7 / 2 = 3.5
Solve using the given values.
C = 2(3.14)(3.5)
C = 2(10.99)
C = 21.98
Therefore, the circumference (perimeter) of the circle is 21.98cm²
Best of Luck!
