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just olya [345]
2 years ago
6

How much of a 3/4 of cup serving is in a 2/3 cup of yogurt?

Mathematics
1 answer:
Veronika [31]2 years ago
3 0

Answer:

8/9

Step-by-step explanation:

could i have brailiest plz it  isnt a must tho thx

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In simplest form, what is 13/15 - 2/5​
natima [27]

Answer:

7/15

Step-by-step explanation:

turn 2/5 to have 15 as the denominator (6/15)

then do 13/15-6/15

answer is 7/15

8 0
2 years ago
Read 2 more answers
According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
I need help with this​
guapka [62]

Answer:

A: Fraction = 11/16 of an inch. Decimal = .6875 inch

B: Fraction = 2 1/2 inch. Decimal = 2.5 inch

Step-by-step explanation:

Each inch is divided by 16ths on the ruler. Count where the measured values lay on the ruler. Once you find the fraction you can divide the fraction to find the decimal answer.

5 0
3 years ago
9.70 x 38.5 can someone work out the problem
Liono4ka [1.6K]
The answer to the question

4 0
3 years ago
What is the value of x in the figure shown below?
Hunter-Best [27]

Answer:

Step-by-step explanation:

for missing angle of triangle ABC

let the missing angle be y

31+111+x=180(sum of interior angle of a triangle is 180 degree)

142+y=180

y=180-142

y=38 degree

x=y(being alternate angles)

x=38 degree

8 0
2 years ago
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