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3 years ago

Kim burns 85 calories per hour hiking. How many calories will Kim burn in h hours?

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

7 0

Idk if I have to put it in a certain way but if she burns 85 cal per h then she will hurt 255cal in 3h

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Find the dimensions of a rectangle with perimeter 116 m whose area is as large as possible. (if both values are the same number,

creativ13 [48]

The dimensions would be 29 by 29.

To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.

Dividing the perimeter by the number of sides, we have

116/4 = 29

This means that both length and width can be 29.

5 0

3 years ago

Can someone help me with this one

bonufazy [111]

Answer:

$x(2x+1)(x-2)$

Step-by-step explanation:

$x(2x^2-3x-2)$

$x(2x^2-4x+x-2)$

$x[2x(x-2)+1(x-2)]$

$x(2x+1)(x-2)$

3 0

3 years ago

Find a ratio that is<br> equivalent to 2:5.

Keith_Richards [23]

Answer:

4:10 hope this helps

Step-by-step explanation:

6 0

3 years ago

Many people think that a national lobby's successful fight against gun control legislation is reflecting the will of a minority

Andre45 [30]

Answer:

The 95% confidence interval of the true proportion of all Americans who are in favor of gun control legislation is (0.5471, 0.5779).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

A random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. This means that $n = 4000$ and $\pi = \frac{2250}{4000} = 0.5625$

Estimate the true proportion of all Americans who are in favor of gun control legislation using a 95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5625 - 1.96\sqrt{\frac{0.5625*0.4375}{4000}} = 0.5471$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5625 + 1.96\sqrt{\frac{0.5625*0.4375}{4000}} = 0.5779$

The 95% confidence interval of the true proportion of all Americans who are in favor of gun control legislation is (0.5471, 0.5779).

8 0

3 years ago

Can someone help me plz

Aliun [14]

Answer:

The answer is 4.

Step-by-step explanation:

8/3 ÷ 2/3 = 8/3 x 3/2 = 4

7 0

3 years ago

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