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g100num [7]
3 years ago
5

Two bottle rockets are simultaneously launched on parallel paths, from 5 feet apart on level ground. After 0.1 second, the rocke

ts are at the same height.
Which theorem or definition can you use to show that the rockets are still 5 feet apart 0.1 second after launch?

Help asap please it's due today :)
Mathematics
1 answer:
meriva3 years ago
7 0

Answer:

The definition of parallel lines are lines that have a constant minimum distance between them at any given point along the lines, such that the lines are the same distance apart all through

Therefore, given that we have;

1) The path of the two bottle rockets are parallel,

2) The initial distance between the two rocket on level ground = 5 feet = The perpendicular (shortest) distance between the two rockets

3) The shortest distance between the rockets having the same height moving on parallel path will be constant = 5 feet

4) The height of the two rockets after 0.1 second = Constant = 5 feet

5) Therefore, by the definition of parallel lines, distance between the two rockets which are at the same height after 0.1 second will still be 5 feet

Step-by-step explanation:

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Mr. and Mrs. Rivers left their house at 10:00 a.m. driving in opposite directions. Mr. Rivers drove at an average speed of 48 mp
Orlov [11]

Answer:

42 miles.

Step-by-step explanation:

It is given that Mr. and Mrs. Rivers left their house at 10:00 a.m. driving in opposite directions.

Speed of Mr. Rivers = 48 mph

Speed of Mrs. Rivers = 36 mph

We need to find the distance between them at 10:30 a.m.

10:30 - 10:00 = 0:30 = 30 minutes = 1/2 = 0.5 hour

Distance covered by Mr. Rivers in half hour = 48 × 0.5 = 24

Distance covered by Mrs. Rivers in half hour = 36 × 0.5 = 18

Total distance covered by both in half hour = 24 + 18 = 42

Therefore, they are 42 miles far from each other at 10:30 a.m.

4 0
4 years ago
Survey data involving two random samples of students at law school are shown. The surveys were taken comparing the age of studen
Crazy boy [7]

Answer:

A and C if you don't believe me look at this link down below

Step-by-step explanation:

https://fsassessments.org/assets/documents/answer-keys-paper/FSA_2018_7M_Practice-Test_Answer-Key_PBT_Final.pdf

8 0
3 years ago
Arjun is twice as old as shriya. If 5 years ago his age was 3 times shriya s age ,then what is arjun s present age?
prisoha [69]

Answer:

20

Step-by-step explanation:

Let Shriya's current age b <em>x</em><em>.</em><em> </em>Arjun's current age will be <em>2</em><em>x</em>.

5 years ago, Arjun's age was <em>2</em><em>x</em><em>-</em><em>5</em><em> </em>and Shriya's age was <em>x</em><em>-</em><em>5</em><em>.</em>

Since Arjun's age was 3 times Shriya's age 5 years ago,

<em>2</em><em>x</em><em>-</em><em>5</em><em> </em>= <em>3</em><em> </em><em>(</em><em>x</em><em>-</em><em>5</em><em>)</em>

<em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em>

<em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em>

3 0
3 years ago
Please put an explanation pleaseeeeeeeeeeeee
Ludmilka [50]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
When planning a date night, you have a choice of 2 types of restaurants: pizza (P) or barbeque (B); a choice of 3 types of movie
enot [183]

Answer:

S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}

Step-by-step explanation:

Given

Restaurant = \{P,B\}

Movies = \{R,A,D\}

Post-movie = \{C,I\}

Required

List out the sample space

To do this, we simply pick 1 item in each category, without repetition.

So, we have:

S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}

4 0
3 years ago
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