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HACTEHA [7]
2 years ago
14

Over what interval does this function remain constant? Do not use any spaces in your interval.

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0

Answer:

We conclude that the function remains constant over the interval [0, 2].

Step-by-step explanation:

We know that if x increases from left to right and y remains constant, the function remains constant over a certain interval.

From the given graph below, it is clear that from x = 0 to x = 2 the value of y does not change.

In other words, the value of y remains constant from x = 0 to x = 2.

i.e.

at x = 0, y = 5

at x = 1, y = 5

at x = 2, y = 5

Therefore, we conclude that the function remains constant over the interval [0, 2].

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

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<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

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So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

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