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Soloha48 [4]
4 years ago
15

PLSSSS HELPP ASSPPPP!!!!

Mathematics
1 answer:
Ne4ueva [31]4 years ago
8 0
The rate of change is 1.5
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There are 16 seats in each row of a
AURORKA [14]

Ans

18.75

Step-by-step explanation:

8 0
3 years ago
Verify that:
Lelu [443]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

\displaystyle \left(\cos(x)\right)\left(\cot(x)\right)=\csc(x)-\sin(x)

Note that cot(x) = cos(x) / sin(x). Hence:

\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)

Multiply:

\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Split:

\displaystyle \frac{1}{\sin(x)}-\frac{\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Simplify:

\csc(x)-\sin(x)=\csc(x)-\sin(x)

Problem 2)

We want to verify that:

\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}

Square:

\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}

Factor out the sin²(x) from the denominator:

\displaystyle \frac{1}{\sin^2(x)}\left(1-2\cos(x)+\cos^2(x)\right)=\frac{1-\cos(x)}{1+\cos(x)}

Factor (perfect square trinomial):

\displaystyle \frac{1}{\sin^2(x)}\left((\cos(x)-1)^2\right)=\frac{1-\cos(x)}{1+\cos(x)}

Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

\displaystyle \frac{(\cos(x)-1)^2}{1-\cos^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}

Factor (difference of two squares):

\displaystyle \frac{(\cos(x)-1)^2}{(1-\cos(x))(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}

Factor out a negative from the first factor in the denominator:

\displaystyle \frac{(\cos(x)-1)^2}{-(\cos(x)-1)(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}

Cancel:

\displaystyle \frac{\cos(x)-1}{-(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}

Distribute the negative into the numerator. Therefore:

\displaystyle \frac{1-\cos(x)}{1+\cos(x)}=\displaystyle \frac{1-\cos(x)}{1+\cos(x)}

3 0
3 years ago
Determine the values of the constants B and C so that the function given below is differentiable.
laila [671]
For the function to be differentiable, its derivative has to exist everywhere, which means the derivative itself must be continuous. Differentiating gives

f'(x)=\begin{cases}24x^2&\text{for }x1\end{cases}

The question mark is a placeholder, and if the derivative is to be continuous, then the question mark will have the same value as the limit as x\to1 from either side.

\displaystyle\lim_{x\to1^-}f'(x)=\lim_{x\to1}24x^2=24
\displaystyle\lim_{x\to1^+}f'(x)=\lim_{x\to1}B=B

So the derivative will be continuous as long as B=24

For the function to be differentiable everywhere, we need to require that f(x) is itself continuous, which means the following limits should be the same:

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}8x^3=8
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}Bx+C=24+C

24+C=8\implies C=-16

So, the function should be

f(x)=\begin{cases}8x^3&\text{for }x\le1\\24x-16&\text{for }x>1\end{cases}

with derivative

f'(x)=\begin{cases}24x^2&\text{for }x
5 0
4 years ago
I need help plz:((((((((((
pashok25 [27]

Answer:

a) y=\frac{28}{75}(x-1900)+47.3

b) 86.5 years

Step-by-step explanation:

All values are rounded to 2 decimal places

a) We can find line by using y =mx+b

y=mx+b\\m=\frac{y^{2}-y^{1} }{x^{2}-x^{1}}\\m=\frac{69.7-47.3}{1960-1900} \\m=\frac{22.4}{60} \\m=\frac{28}{75}\\c=y-intercept\\y-intercept=47.3\\y=\frac{28}{75} (x-1900)+47.3

Therefore the line of best fit is y=\frac{28}{75}(x-1900)+47.3\\

b) We can do this by using the formula of the best fit line to estimate the life expectancy of someone born in 2005

y=\frac{28}{75}(x-1900)+47.3\\y=\frac{28}{75}(2005-1900)+47.3\\y=\frac{28}{75}\times105+47.3\\y=86.5

Therefore the estimated life expectancy of someone born in 2005 is 86.5 years

PS. Please give brainliest answer this was a lot of working out

3 0
3 years ago
I need help with 5 1\2× 3 1\4 =?
sattari [20]

5 1/2 * 3 1/4


1 + 5 . 2/2 * 1 + 3 . 4/4 = 11/2 * 13/4 = 11 . 13/2 . 4 = 143/8 = 7 + 17 . 8/8 = 17 7/8


= 17 . 875



Detailed explanation of solution:


5 1/2 * 3 1/4


Transform the first mix number to improper fraction:


5 1/2 = 1 + 5 . 2/2 = 11/2




Transform the second mix number to improper fraction:


3 1/4 = 1 + 3. 4/4 = 13/4




Multiplying two fractions:


11/2 * 13/4 = 11 . 13/2 . 4 = 143/8




Since the numerator is greater than the denominator, We convert the improper fraction to mix fraction:


143/8 = 7 + 17.8/8


= 17 7/8 (Decimal: 17. 875)








Hope that helps!!!!!! ( Answer: 17 7/8, (Decimal: 17.875)




3 0
3 years ago
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