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vova2212 [387]
3 years ago
10

(3x+23x +32) = (x+6)

Mathematics
2 answers:
Ksju [112]3 years ago
7 0

Answer:

x = -26/25

Step-by-step explanation:

(3x+23x +32) = (x+6)

Combine like terms

26x +32 = (x+6)

Subtract x from each side

26x -x +32 = x+6-x

25x +32 = 6

Subtract 32 from each side

25x+32 -32 = 6-32

25x = -26

Divide each side by 25

25x/25 = 26/25

x = -26/25

mars1129 [50]3 years ago
5 0
The answer is x=-26/25

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\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

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Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

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