Answer:
D. Miko found an incorrect quotient and checked her work using multiplication incorrectly
Step-by-step explanation:
We are given the equation
This can be rewritten as
Miko's work is incorrect as she did not multiply by the reciprocal of denominator's fraction. Instead she just multiplied by that fractions.
Great Job! they are all correct. :)
Good luck in your next tests.
There are 4 sides in a triangular pyramid. So just multiply 80m2 by 4
80×4=24
now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.
so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.
therefore, we settle for the endpoints, 4 and 6,
f(4) =3 and f(6) = 7
doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.
What do you mean, "solve"?
y = -4(x-2)² + 4
the line is a parabol with a maximum (2;4)
it's roots are -4(x-2)² + 4 = 0 => (x-2)² = 1 => x-2 = 1 => x = 3
=> x-2 = -1 => x = 1
symetrical axe: x = 2
is that all you need?
