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3 years ago

Last year a winter coat cost $175. This year the price increased 15%. What is the new price?

Mathematics

1 answer:

Gennadij [26K]3 years ago

5 0

Answer:

The new price of the coat is $201.25

Step-by-step explanation:

The price will be higher since this is an increase.

Percent increase = (new price - old price) / old price

Substituting what we know

.15 = (new price -175)/175

Multiplying each side by 175

.15*175 = new price by 175

26.25 = New price-175

Add 175 to each side

26.25+175 = new price-175+175

201.25 = new price

The new price of the coat is 201.25

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What sum of money amounts Rs.3250 in 6 yrs at the rate of 5%?

kvasek [131]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the multiplier:

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The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe

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Let the width be x.

Length is 8 feet more than width. Length = x + 8

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width increased by 4, that is, (x + 4)
Length decreased by 5, (x + 8 - 5) = (x + 3)

Area = (x + 4)(x +3)

Area remains the same

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A sphere has a radius of 1.5 inches.

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3 years ago

Although companies would like consumers to believe that Identity theft protection is an

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The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is $\bar x =\frac{1}{n} \sum X_i$ where n is the number of observations; $X_i$ are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is $\bar x = \frac{1}{N}\sum f_ix_i$ where $N =\sum f_i$ and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is $m_e = 14.99$ , and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations $x_i$ and frequencies $f_i$ .

Then, the mean is calculated by

$\bar x = \frac{1}{N}\sum f_ix_i$

Where $N =\sum f_i$ (Sum of frequencies)

The median is calculated by

$m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.$

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

$\bar x =\frac{1}{n} \sum X_i$

Where n = 25; $X_i$ - n observations

On substituting,

Mean $\bar x$

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

$\bar x = \frac{1}{N}\sum f_ix_i$

Where N = 25;

On substituting,

$\bar x$ <em> </em>= 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

= 1/25 (402.42)

= 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So, the median $m_e$ = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

Learn more about frequency distribution here:

brainly.com/question/27820465

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2 years ago