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ankoles [38]
3 years ago
13

Which is bigger square root of 1001 - square root of 1000 or 1/10?

Mathematics
1 answer:
IgorC [24]3 years ago
8 0
Square root of 1001=10.0033
square root of 1000=10
so 10.0033-10=0.0033
1/10=0.1
so, 1/10 is bigger than square root of 1001- square root of 1000
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87/100 in simplest form
Paladinen [302]

The fraction Is already in its simplest form :)


They do not have any common factors

6 0
2 years ago
You are given a loaded six-sided die. Such a die can produce any integer from 1 to 6. The die rolls a 4 three times as often as
beks73 [17]
I would say 6 bc it’s a die of 6 and u get it 6 times
6 0
3 years ago
Find the discriminant of the following equation.<br> 4x2 + 16x + 16 = 0 ...?
kenny6666 [7]

Discriminant = b^2 - 4ac

a = 4

b = 16

c = 16

16^2 - 4(4 x 16)

256 - (4x64)

256 - 256 = 0

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7 0
2 years ago
9-3*1/3*98=<br><br> 6-*87/8+85647-552=<br><br><br> 254+968*8
sp2606 [1]

Answer:

don't you have a calculator? just use that

6 0
2 years ago
Which rules of exponents will be used to evaluate the expression. Check all that apply
julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

<h2>Why?</h2>

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers [(7)^{5}*(7)^{3}]

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

(7)^{5+3}

(7)^{8}

Then,

We have a power of a power case, which involves multiplying the exponents:

[(7)^{5}*(7)^{3}]^{-4}

Exponents: 3 and -4

Then,

(7)^{8*-4}

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

(7)^{-32}=\frac{1}{7^{32} }

Have a nice day!

6 0
3 years ago
Read 2 more answers
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