The 8 and 4 are like terms and can be added and since it is all addition we wind up with:
9t +12
We have three <span>face card and 4 groups of cards</span>
3*4=12
12/52=3/13
p(a)=3/13
Answer:
The two scenarios differ.
P(Scenario A) = 0.107
P(Scenario B) = 0.265
Step-by-step explanation:
The two scenarios are different because for the second one you are alredy assuming that the first 3 cards are not hearths, and for that reason, B is more likely to happen that A.
For B to happen, you need to notice that since you remove 3 cards from your deck that are not hearts, then your deck has only 49 cards, and 13 of them are hearts. The probability for a heart to show up is, as a result 13/49 = 0.265 because you have 13 favourable cases from 49 possible.
For A, you need the first card to be anything but a heart. Since 13 cards of the deck are herts, 39 are not, and the probability of that hapening is 39/52 = 3/4. After you remove your first card, the probability of the second one not being heart is 38/51, and the probability for the third one is 37/50 (you are removing one favourable case and one case for the total of cases each time). The probability for the fourth card being a heart assuming that the first three are not was calculated before and it gives us a result of 13/49.
Multiplying everything, we obtain that
P(A) = 3/4*38/51*37/50*13/49 = 0.107.
ANSWER: X>-3, when you divide by a negative with <> signs, you flip the sign
Answer:
Assuming that the x2 is x squared, B
Step-by-step explanation:
(1)(1) + 5(1) - 6 = 1 + 5 - 6 = 6 - 6 = 0
(-6)(-6) + 5(-6) - 6 = 36 - 30 - 6 = 6 - 6 = 0
