Question

the perimeter of a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width of the rectangle, in feet.

Answer 1

Answer:

The width of the rectangle is 7 feet.

Step-by-step explanation:

Given:

The perimeter of a rectangle is 54 feet, and the length is 13 feet more than the width.

Now, to find the width of the rectangle.

Let the width be $x.$

So, the length is $13+x.$

Perimeter = 54 feet.

Now, to get the width we put formula:

$Perimeter=2(length+width)$

$54=2(13+x+(x))\\54=2(13+x+x)$

$54=2(13+2x)$

$54=26+4x$

Subtracting both sides by 26 we get:

$28=4x$

Dividing both sides by 4 we get:

$7=x\\x=7\ feet.$

Therefore, the width of the rectangle is 7 feet.