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Marrrta [24]
3 years ago
10

the perimeter of a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width of the rectangle, in feet

.
Mathematics
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

The width of the rectangle is <u>7 feet</u>.

Step-by-step explanation:

Given:

The perimeter of a rectangle is 54 feet, and the length is 13 feet more than the width.

Now, to find the width of the rectangle.

Let the width be x.

So, the length is 13+x.

Perimeter = 54 feet.

Now, to get the width we put formula:

Perimeter=2(length+width)

54=2(13+x+(x))\\54=2(13+x+x)

54=2(13+2x)

54=26+4x

<em>Subtracting both sides by 26 we get:</em>

28=4x

<em>Dividing both sides by 4 we get:</em>

7=x\\x=7\ feet.

Therefore, the width of the rectangle is 7 feet.

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Step-by-step explanation:

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7 0
2 years ago
Let f(x) = x^2 + 6x.
rusak2 [61]

Answer:

(A) The slope of secant line is 18.

(B) The slope of secant line is h+16.

Step-by-step explanation:

(A)

The given function is

f(x)=x^2+6x

At x=3,

f(3)=(3)^2+6(3)=27

At x=9,

f(9)=(9)^2+6(9)=135

The secant line joining (3,27) and (9,135). So, the slope of secant line is

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{135-27}{9-3}=18

The slope of secant line is 18.

(B)

The given function is

f(x)=x^2+6x

At x=5,

f(5)=(5)^2+6(5)=55

At x=5+h,

f(5+h)=(5+h)^2+6(5+h)=h^2 + 16 h + 55

The secant line joining (5,55) and (5+h,h^2 + 16 h + 55). So, the slope of secant line is

m=\dfrac{h^2 + 16 h + 55-55}{5+h-5}

m=\dfrac{h^2 + 16 h }{h}

m=h+16

The slope of secant line is h+16.

4 0
3 years ago
Use the interactive to find an expression equivalent to
Jobisdone [24]

Answer:

I solved it and my answer is number 1

7 0
3 years ago
Plzz anyone solve all answers plzzzzzzzz​
algol13

You posted a lot of problems here. In the future please only post one problem at a time. Thank you.

I'll do the first two problems to get you started. Hopefully it will help you finish off the rest of the questions.

==========================================

Problem 1

{18, a, b, -3} is an arithmetic sequence or arithmetic progression (AP).

This means we have some number d added on to each term to get the next term.

first term = 18

second term = first term + d = 18+d = a

third term = second term + d = (18+d)+d = 18+2d = b

fourth term = third term + d = (18+2d)+d = 18+3d = -3

----

Let's solve that last equation for d

18+3d = -3

18+3d-18 = -3-18

3d = -21

3d/3 = -21/3

d = -7

----

The value d = -7 tells us to add -7 to each term to get the next term. In other words, we subtract 7 from each term to get the next term

first term = 18

second term = first term + d = 18+d = 18+(-7) = 18-7 = 11

third term = second term + d = 11+d = 11+(-7) = 11-7 = 4

fourth term = third term + d = 4+d = 4+(-7) = 4-7 = -3

----

We see that a = 11 and b = 4 are the second and third terms respectively.

Therefore, a+b = 11+4 = 15

-------------

<h3>Answer: 15</h3>

==========================================

Problem 2

A multiple of 4 is in the form 4*n for some integer n, ie n is a whole number.

We want to know which values of 4*n are between 10 and 250.

----

Divide both 10 and 250 by 4 to get the following

10/4 = 2.5

250/4 = 62.5

If n = 2, then 4*n = 4*2 = 8 is not between 10 and 250; however n = 3 will make 4*n = 4*3 = 12 to be between 10 and 250. We see that n = 3 is the smallest possible allowed value.

If n = 62, then 4*n = 4*62 = 248 is between 10 and 250; while n = 63 will make 4*n too big because 4*63 = 252. The largest n can get is n = 62

----

The question posed in question 2 is equivalent to asking the following: "How many values are in the set {3, 4, 5, ..., 60, 61, 62}?"

You could count all of the values in the set, but that exercise is very tedious busywork. There's a much faster way. First lets consider the set below

{a, a+1, a+2, ..., b-2, b-1, b}

where a,b are integers. Basically this set starts at 'a', counts up until we get to 'b'. The handy formula

c = b-a+1

will provide the exact count of values in the set {a, a+1, a+2, ..., b-2, b-1, b}

----

In this case, a = 3 and b = 62, making

c = b-a+1

c = 62-3+1

c = 60

There are 60 values in the set {3, 4, 5, ..., 60, 61, 62}

There are 60 multiples of four that are between 10 and 250.

-------------

<h3>Answer: 60</h3>
4 0
3 years ago
What is the product in distributive property for 7x63
Sauron [17]
Distributive property is
a(b+c)=ab+ac

we can make it easier by splitting up 63 into 60+3

so
7(63)=7(60+3)=7*60+7*3=420+21=441
7 0
3 years ago
Read 2 more answers
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