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2 years ago

Plzzzzz help!!!!! I will give brainliest

Mathematics

1 answer:

Vitek1552 [10]2 years ago

3 0

Answer:

<h2>10.88inches</h2>

Step-by-step explanation:

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Which statement correctly finds the interquartile range for the set of data represented by the box plot?

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

Median: 9.5

Lower Quartile: 6

Upper Quartile: 11

Interquartile Range: upper quartile - lower quartile = answer

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2 years ago

Shadow Software company earned a total of 800,009 selling programs during the year 2012. 125,300 of taht amount was used to pay

Softa [21]

Subtract 125,300 from 800,009. From there you find that they made 674,709 in profit. Answer is 674,709

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3 years ago

Solve for w p=1.2w/h^2

andreyandreev [35.5K]

Solve for w:
p = (1.2 w)/h^2
(1.2 w)/h^2 = (6 w)/(5 h^2):
p = (6 w)/(5 h^2)
p = (6 w)/(5 h^2) is equivalent to (6 w)/(5 h^2) = p:
(6 w)/(5 h^2) = p
Multiply both sides by (5 h^2)/6:
Answer: w = (5 h^2 p)/6

6 0

3 years ago

Solve:<br> 3x=12<br> 05<br> 36<br> 04

Natasha2012 [34]

Answer:

x=04

Step-by-step explanation:

8 0

2 years ago

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

3 years ago