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STALIN [3.7K]
2 years ago
10

Plzzzzz help!!!!! I will give brainliest

Mathematics
1 answer:
Vitek1552 [10]2 years ago
3 0

Answer:

<h2>10.88inches</h2>

Step-by-step explanation:

You might be interested in
If 4 gal of premium unleaded gasoline costs $15.04, how much would it cost to completely fill a tank whose capacity is 9-gal?
Sveta_85 [38]

Answer:

$33.84 cents

Step-by-step explanation:

Given the following question:

4 gallons = 15.04
1 gallon = ?

How much for 9 gallons?

To find the answer we have to find how much one-gallon costs since we already know how much it costs for 4 gallons of this unleaded gasoline.

15.04\div4
15.04\div4=3.76
=3.76

One gallon of this gasoline costs $3.76 now we need to find how much it costs for 9 gallons.

3.76\times9=33.84
=33.84

For nine gallons of gasoline it will cost you "$33.84 cents."

Hope this helps.

4 0
2 years ago
HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME
Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















3 0
2 years ago
Read 2 more answers
Weekly demand for milk at a small grocery store is normally distributed with a mean of 251 gallons per week and standard deviati
slavikrds [6]

Solution

Given

mean = 251

standard deviation = 33

(a)

\begin{gathered} P(Z

Hence, X = 300

7 0
1 year ago
Read 2 more answers
7(9k + 6m) <br><br><br>(50 points)
vladimir1956 [14]

21 • (3k + 2m)

Step by step solution :

Step  1  :

Step  2  :

Pulling out like terms :

2.1     Pull out like factors :

  9k + 6m  =   3 • (3k + 2m)  

Final result :

 21 • (3k + 2m)

6 0
3 years ago
Read 2 more answers
How do you simplify that question? For algebra 1.
motikmotik
\left( \sqrt{x^{-3}} \right)^5 =  \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }


<span>Explanation for the last step:</span>
\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}

7 0
3 years ago
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