Answer:
Independent events
Step-by-step explanation:
Given that:
Ramiro draws a marble from a jar without replacement and then flips a coin
Let 
be the event that Ramiro draws a marble without replacement and;
Let 
be the event of flipping a coin.
Let's have an analogy so that we can better understand the concept of independent and dependent events.
Consider a random experiment in which a marble is drawn from a jar without replacement and a fair coin is flipped together.
The event does not in any way affect the event of a head or a tail showing up in a flip of a coin.
Therefore, we say that and are independent events.
Suppose the event affects or influence the event , then we can say they are dependent events.
Answer:
Here is the full proof:
AC bisects ∠BCD Given
∠CAB ≅ ∠CAD Definition of angle bisector
DC ⊥ AD Given
∠ADC = 90° Definition of perpendicular lines
BC ⊥ AB Given
∠ABC = 90° Definition of perpendicular lines
∠ADC ≅ ∠ABC Right angles are congruent
AC = AC Reflexive property
ΔCAB ≅ ΔCAD SAA
BC = DC CPCTC
Answer: y = 4 and x = 1
Step-by-step explanation:
when y is 2, x is 0.5
when y is 4, x is 1
.(+ 2) .(+ 0.5)
.(+ 2) .(+ 0.5)
.(+ 2) .(+ 0.5)
.(+ 2) .(+ 0.5)
the rule is that y is 4 times larger than x
For the answer to the question above asking to e<span>xplain why the events "getting a black marble" and "getting a red marble" are mutually exclusive.
</span>A marble can have only one color, so you cannot choose a marble that is both black and red. Therefore the events are mutually exclusive (cannot happen simultaneously)
Answer:
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