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Bogdan [553]
3 years ago
11

Which pairs of quadrilaterals can be shown to be congruent using rigid motions?

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

Answer:

quadrilateral 1 and quadrilateral 2 NOT CONGRUENT

quadrilateral 1 and quadrilateral 3 CONGRUENT

quadrilateral 1 and quadrilateral 4 CONGRUENT

quadrilateral 2 and quadrilateral 3 NOT CONGRUENT

quadrilateral 2 and quadrilateral 4 NOT CONGRUENT

quadrilateral 3 and quadrilateral 4 CONGRUENT

Step-by-step explanation:

quadrilateral 1 and quadrilateral 2 NOT CONGRUENT

quadrilateral 1 and quadrilateral 3 CONGRUENT:

rigid motion: reflection

axis of reflection: y=x

quadrilateral 1 and quadrilateral 4 CONGRUENT:

rigid motions: translation and reflection

axis of reflection y=0

quadrilateral 2 and quadrilateral 3 NOT CONGRUENT

quadrilateral 2 and quadrilateral 4 NOT CONGRUENT

quadrilateral 3 and quadrilateral 4 CONGRUENT:

rigid motions: translation and reflection

axis of reflection: x=0

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Y=3x+7 solve this system of equation using any method
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Answer:

x=2, y=13

Step-by-step explanation:

In order to get this by addition which is the easiest way for this you want to take both equations

y=3x+7 and y=-4x+21 and move x to the other side of the equation so it is like  4x+y=21 and -3x+y=7 like that now you have to get rid of one of the exponents and the easiest one to get rid of is y so I'm going to multiply -3x+y=7 by negative 1 so it becomes 3x-y=-7 that way the equations value has not changed since I multiplied both sides and now when I add

4x+y=21 and 3x-y=-7 It'll look like

4x+y=21

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3 0
3 years ago
There are some monkeys in the zoo. 60% are young monkeys and the remaining are baby and old monkeys. The ratio of baby monkeys t
USPshnik [31]

Answer:

There are 60 monkeys in the Zoo

Step-by-step explanation:

In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.

Let’s have the total number of monkeys be m.

60% are going monkeys. This means number of young monkeys is 0.6m.

The number of baby and old monkeys is obviously 0.4m.

Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m

Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.

Let’s project this mathematically;

This means ;

0.6m - 0.3m = 18

0.3m = 18

m = 18/0.3

m = 60

There are 60 monkeys in the zoo

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Answer:

7x ≥ 70

Step-by-step explanation:

5x + 2x ≥ 70

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Hope this helps!

-sruthi123

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Check the picture below.

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