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il63 [147K]
3 years ago
5

The population in England goes up by 1/5 every year. If the population was £20mil in 2008 what would be the population in 2010?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

1/5 = 20%

20.000.000 x 20% =4.000.000 / year

from 2008 to 2010 is : 2 years

So the population in 2010 is : 20.000.000 + ( 4.000.000 x 2 ) = 28.000.000 population

Step-by-step explanation:

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12, Increase

Step-by-step explanation:

12 is by far the lowest in the set, and removing the number would raise the mean.

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A rectangular prism measures 2 2/5 inches by 3 1/5 inches by 2 inches.
schepotkina [342]

Step-by-step explanation:

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Express x^-1 y^-2/z^-3 with positive exponents.
Nimfa-mama [501]

\frac{x {}^{ - 1}y {}^{ - 2}  }{z {}^{ - 3} }

if the upper number got power of negative it will go down and the down will go up

So that,

\frac{z {}^{3} }{x {}^{1} {y}^{2}  }

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3 years ago
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Someone help me please. I don't just want the answer, I need an explanation on how it's done too.​
NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

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=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

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4 0
3 years ago
Miguel bought 8 equally priced pens for $3.84.
11111nata11111 [884]

<u>Answer:</u>

  • For 15 pens, the cost is $7.2

<u>Step-by-step explanation:</u>

<u>We know that:</u>

  • 8 pens = $3.84

<u>Work:</u>

  • 8 pens = $3.84

Divide the RHS:

  • => 1 pen = 3.84/8
  • => 1 pen = 0.48

Multiply the RHS:

  • => 15 pens = 0.48 x 1
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Hence, <u>for 15 pens, the cost is $7.2</u>

Hoped this helped.

BrainiacUser1357

7 0
2 years ago
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