Whole numbers are 0,1,2,3 etc. so it would be 1 and 2
Answer and Step-by-step explanation: The graph is shown in the attachment.
a. ΔR on [1,2] is mathematically expressed as:
ΔR = R(2) - R(1)
which means difference of population of rabbits after 2 months and after 1 month.
R(2) = 
![\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]](https://tex.z-dn.net/?f=%5CDelta%20R%20%3D%20100%5B%5Cfrac%7B4%7D%7B5%7D%20-%20%5Cfrac%7B2%7D%7B5%7D%20%5D)
40
Difference of rabbits between first and second months is 40.
b. R(0) = 100(
)
R(0) = 0
Initially, there no rabbits in the population.
c. R(10) = 
R(10) = 400
In 10 months, there will be 400 rabbits.
d. R(t) = 500
t = 12.5
In 12 and half months, population of rabbits will be 500.
Answer:
First i need you to tell me the pattern and then i will help you :)
Step-by-step explanation:
-4/1
-1/0
2/1
5/2
8/3
or put then as ratios the same way i am not so sure
Let’s call the numbers x and y. Let’s also say that x is the smaller of the two. Since their difference (the answer you get when you subtract is 44 and a half) we know that y-x=44.5
Next we are told that if the smaller increases 7 times (that means 7x) their difference would be 10 3/14. Let’s write that as a fraction. It is 14x10+3 over 14. That is 143/14.
So this means y-7x=143/14.
We have two equations and two unknowns (a system of equations). We write one over the other and subtract them to get:
y-x=44.5
y-7x=143/14
Subtracting yields:
(y-y)+(-x - - 7x) = 44.5 - 143/14
6x = (89/2) - (143/14)
6x= 623/14 - 143/14
6x=480/14
X= (480/14)(1/6)
X=80/14
x= 40/7 = 5 5/7
Since y-x=89/2
We get y - 40/7 = 89/2
Y = 40/7 + 89/2
Y = 80/14 + 623/14
Y = 703/14 = 50 3/14
We have by the intermediate value theorem that if a continuous function takes values both above and below zero at 2 points, there is a zero of the function in-between. We have that polynomials are continues. Let's calculate f(-6) and f(-5). f(-6)=-36 while f(-5)=-1. Thus, we cannot conclude that there is a root between them.
F(-2)=8, f(-1)=-1, so there is a flip; a zero must exist between them.
F(1)=-1, f(2)=20, so again there is a change of signs.
f(-5)=-1, f(-4)=14 so there is a root still.
We have that the only choice that does not have a root between the integers is choice a.
