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3 years ago

Simplify the algebraic expression y²+11y-6y+y²

Mathematics

2 answers:

Radda [10]3 years ago

8 0

Answer:

2y^2 + 5y

Step-by-step explanation:

the two y squared add up to 2 y squared

11y - 6y = 5y

lubasha [3.4K]3 years ago

3 0

The simplified expression should be y^4 + 17y

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Use interval notation to describe. John is at least 26 years old.

andrezito [222]

John= greater than or equal to 26 (a >26 with a line under the symbol)

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3 years ago

ABCD is a square. M is the midpoint of BC and N is the midpoint of CD. A point is selected at random in the square. Calculate th

almond37 [142]

Answer:

1/8 or 0.125

Step-by-step explanation:

Let x be the length of the sides of the square ABCD.

Therefore, the length of CN and CM is x/2.

The area of the triangle MCN is:

$A_t = \frac{0.5x*0.5x}{2}=\frac{x^2}{8}$

The area of the square ABCD is:

$A_s =x*x =x^2$

Thus, the probability that a random point lies in the triangle MCN is:

$P=\frac{A_t}{A_s}=\frac{\frac{x^2}{8}}{x^2}=\frac{1}{8}=0.125$

The probability that the point will lie in the triangle MCN is 1/8 or 0.125.

8 0

3 years ago

According to a certain website, wine critics generally use a wine-scoring scale to communicate their opinions on the relative qu

const2013 [10]

Answer:

$\bar x = 82$

$\sigma = 9.64$

Step-by-step explanation:

Given

$n = 12$

$87\ 91\ 86\ 82\ 72\ 91\ 60\ 77\ 80\ 79\ 83\ 96$

Solving (a); Point estimate of mean

To do this, we simply calculate the sample mean

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{87+ 91+ 86+ 82+72+91+60+77+80+79+83+96}{12}$

$\bar x = \frac{984}{12}$

$\bar x = 82$

Solving (b); Point estimate of standard deviation

To do this, we simply calculate the sample standard deviation

$\sigma = \sqrt{\frac{\sum(x-\bar x)^2}{n - 1}$

$\sigma = \sqrt\frac{(87-82)^2+ (91-82)^2+ ....+ (79-82)^2+ (83-82)^2+ (96-82)^2}{12-1}$

$\sigma = \sqrt\frac{1022}{11}$

$\sigma = \sqrt{92.91}$

$\sigma = 9.64$

Note that: The sample mean and the sample standard deviation are the best point estimators for the mean and the standard deviation, respectively.

Hence, the need to solve for sample mean and sample standard deviation

3 0

3 years ago

In a class of 30 students, 6 have a brother and 12 have a sister. There are 14 students

Elena-2011 [213]

30 students

14 have no siblings

that leaves 16 with siblings

6 have brothers and 12 have sisters which = 18 so 2 of the students have both a brother and a sister

2/30 students have a brother and a sister

1/15 chance

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3 years ago

If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?

zepelin [54]

Honestly this problem you can use both x and y but x tends to be the easier one to use and i would use the first equation because it is easier to solve because all the numbers are even.

7 0

3 years ago