What is the answer to the promblem. 4 6/8- 1 1/8

Mathematics

2 answers:

saul85 [17]3 years ago

6 0

The answer is 3 5/8

melomori [17]3 years ago

3 0

Answer:4

Step-by-step explanation:

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In the early months of some year one site added 0.2 million new accounts everyday. At this rate, how many days would be needed t

WITCHER [35]

60 days, I think. Sixty times zero point two is twelve.

3 0

3 years ago

Consider the following equation.

EastWind [94]

The approximate solution of the above equation is: 55/15 (Option A). This is solved using the quartic formula, not quadratic equation.

<h3>What is the Quartic Formula?</h3>

The quartic formula has up to four various solutions including real and imaginary numbers. Read on for more explanation.

<h3>What is the solution to the above question?</h3>

First we restate the above equation:

x²-3x+2= √(x-2) + 2

Next we remove square roots

$x^{4}$ - 6x³ + 9x² = x - 2

Add two to both sides

→ $x^{4}$ - 6x³ + 9x²+2 = x - 2 +2

→ $x^{4}$ - 6x³ + 9x²+2 = x

Subtract X from both sides

→ $x^{4}$ - 6x³ + 9x²+2 -x = x -x

→ $x^{4}$ - 6x³ + 9x²+2 - x= 0

Using the Quartic formula to solve the fourth order equation:
a $x^{4}$ + bx³ + cx² + dx + e

The resolution of x is given as:

x = 2.691085, 3.346753

Because the fraction nearest to 3.4 is 55/16

hence, the correct answer is Option A.

Learn more about quadratic equations at;
brainly.com/question/25841119
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6 0

2 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em> $h(t)$ <em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em> $h(t) = 3 +90\cdot t -16\cdot t^{2}$ <em>, where </em> $t$ <em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$