All categories

2 years ago

4) A rectangle as a length which is twice its width.

Mathematics

1 answer:

Yuki888 [10]2 years ago

6 0

Answer:

Step-by-step explanation:

2 is it's length while in the perinthesis is x for its length plus the width which is doubled, explained by the x.

You might be interested in

Simply 9+3(8-3(7-5))-4

EastWind [94]

Answer:

Step-by-step explanation:

9+3(8-3(7-5))-4
9+3(8-3(2))-4
9+3(8-6)-4
9+3(2)-4
9+6-4
15-4
11

I first delt with simplifying the parentheses till step five. Then in five I just added 9+6 because it came before the -4. But PEMDAS is very important when doing these problems because it tell you the order

P (parentheses)
E (exponents)
M (multiply)
D (divide)
A (add)
S (subtract)
**the biggest thing is that with multipe and divide it depends what comes first. If you see divide before multipe in the problem just do it that way. It is the same way with add and subtract but The multiple/divide group ALWAYS comes BEFORE add/subtract

4 0

3 years ago

If collecte 63 cans which is 21%. How many cans are 46%. And how many is 33% ?

EleoNora [17]

If 63 cand are 21% we must find out what 1% is
To do that we must divide 63 by 21
63/21 = 3
So 1%=3 cans
To find out what a percentage equals we must times it by 3
46 * 3 =138 cans
33*3 = 99 cans
Hope this helps :)

7 0

3 years ago

John joined a fitness club that has a membership fee of $30 +25 per month. Mary’s club has a fee of 50 and charges 15 per month.

zmey [24]

Just solve until the answers are the same

25 times x plus 30 for John

15 times x plus 50 for Mary

8 0

3 years ago

There are 99 males and 121 females participating in a marathon. What participants are females?

notsponge [240]

Answer:

121..??

Step-by-step explanation:

4 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago