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CaHeK987 [17]
3 years ago
5

If an interior angle of a regular polygon measures 108°, how many sides does the polygon have?

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0

Answer:

5 sides

Step-by-step explanation:

Use the formula for the measure of an interior angle of a polygon

\frac{(n - 2)180}{n}

Solve for n (the number of sides):

108 = \frac{(n - 2)180}{n}

108n = (n - 2)180

108n = 180n - 360

-72n = -360

n = 5

So, the polygon has 5 sides.

PilotLPTM [1.2K]3 years ago
5 0

Answer:

5

Step-by-step explanation:

<u>(n-2)180 = 108</u>

          n

Distribute

180n-360=108n

-360=-72n

5=n

n=5

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10 n-3 = 7n+21

Add 3 to both sides :

10n-3+3=7n+21+3

10n=7n+24

Subtract  7 n from both sides:

10n-7n=7n+24-7n

3n=24

Divide both sides by 3 :

\frac{3n}{3} = \frac{24}{3}

n = 8

hope this helps!
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6 0
3 years ago
2y/5y cube + 4y square + 6y
timama [110]

Answer:

here down is the answer

(2y/5y)^3+4y^2+6y

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16y^2+6y+8/125=0

it is in the form of quadratic equation

formula :

x=(-b+-square root of b^2-4ac) /2a

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x=(-b+-square root of b^2-4ac)/2a

x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation

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