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Gemiola [76]
3 years ago
15

[x÷(y–1)](−4)–[xy+(−3)]÷(−1) if x=−5, y=−2

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0
The result is 1/3.

_____
The first attempt in the attached picture has parentheses in the wrong place for the second term. This simplifies to
.. (-5/-3)*(-4) +(10 -3)
.. = -20/3 +7
.. = -(6 2/3) +7
.. = 1/3

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Step-by-step explanation:

When it comes to art, you may need to read books in order to understand how to paint. That is as logical I can get :)

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A truck can be rented from Company A for ​$70 a day plus ​$0.50 per mile. Company B charges ​$20 a day plus ​$0.60 per mile to r
r-ruslan [8.4K]

Answer:

The rental cost for Company A and Company B will be the same after 500 miles

Step-by-step explanation:

The total cost of renting a truck from Company A can be expressed as;

Total rental cost(Company A)=Cost per day+Total rate

where;

Cost per day=70

Total rate=rate per mile×number of miles (m)=(0.5×m)=0.5 m

replacing;

Total rental cost(Company A)=70+0.5 m...equation 1

2. The total cost of renting a truck from Company B can be expressed as;

Total rental cost(Company B)=Cost per day+Total rate

where;

Cost per day=20

Total rate=rate per mile×number of miles (m)=(0.6×m)=0.6 m

replacing;

Total rental cost(Company B)=20+0.6 m...equation 2

Equating equation 1 to equation 2

70+0.5 m=20+0.6 m

0.6 m-0.5 m=70-20

0.1 m=50

m=50/0.1

m=500 miles

The rental cost for Company A and Company B will be the same after 500 miles

7 0
3 years ago
What’s the equation of a line?
Akimi4 [234]

Answer:

1. y= 3x -10

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3. y= x -9

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5 y= -x + 2 1/2

6 0
2 years ago
What is the hcf of 45 and 100
Ira Lisetskai [31]

Answer:

45 100

/ \ / \

3 × 15 2×50

/ \ / \

3× 5 2×25

/ \

5×5

45 : 3×3×5

100: 2×2×5×5

common : 3×5

15

HCF: 15

6 0
3 years ago
Find the cosine of L
aleksandr82 [10.1K]

Answer:

0.42

Step-by-step explanation:

use the attached as reference

recall that for a right (90°) triangle, with any acute angle θ,

cos θ = length of adjacent side / length of hypotenuse

in our case, for angle I, the adjacent side is HI = 36 units and the hypotenuse is IJ = 85 units

by the above formula,

cos I = length of adjacent side / length of hypotenuse

= 36 / 85

= 0.42353

= 0.42 (rounded to nearest hundredth)

4 0
3 years ago
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