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olga2289 [7]
3 years ago
6

Find the difference (2m+3)-(7m-5)

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

- 5m + 8

Step-by-step explanation:

Given:

(2m + 3) - (7m - 5)

If you want to find the differences between two values, it means you are to subtract

(2m + 3) - (7m - 5)

This means subtract (7m - 5) from

(2m + 3)

Step 1: Open parenthesis

(2m + 3) - (7m - 5)

= 2m + 3 - 7m + 5

Group like terms

= 2m - 7m + 3 + 5

= - 5m + 8

Or

= 8 - 5m

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Mixed Number Form:

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Which of the following is a good survey?A) You survey the football team to determine if the school should purchase a new weight
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Answer:

Your business partner is correct.

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<u>Stats - Correlations</u>

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  • Negative means that is is trending downwards

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If we were to draw a best line of fit into the scatterplot, we would see that we would get a positive slope and a positive line.

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McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
3 years ago
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