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Harlamova29_29 [7]
3 years ago
10

the length of a rectangle is 7 yd more than 5 times the width. the perimeter is 150 yd. find the length and the width.

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0
P = 2(L + W)
P = 150
L = 5W + 7

150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width

L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length
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Answer:

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Step-by-step explanation:

There's an actual algebra method for this, but this is my method because I find it way easier to remember.

Since the most you can discount out of an item is 100% (well, it's considered free then) let's subtract 100 - 34, which is 66.

Now, turn it into a decimal because it makes the numbers easier- 0.66.

Since when you're finding the discount of an original price, you multiply the original price by the discount- instead for finding the original price for a discounted item we divide $429 by 0.66 instead, since when you divide a number by another number that's under 1 the quotient is a larger number.

So, 429 ÷ 0.66 = 650.

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Step-by-step explanation:

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3 years ago
Diego and Jada are both trying to write an expression with fewer terms that is equivalent to
UkoKoshka [18]

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Step-by-step explanation:

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3 years ago
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Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

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5 0
3 years ago
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